$_SESSION array

[mistrig]

Hi, I'm trying to create a session array and give a dynamic name.

I tried something like this but I get only the last entry i made (key=0) :

    $qid = $_POST['pstq'];
        $_SESSION[$qid] = array();
 
    foreach ($_SESSION[$qid] as $key=>$value) {
    echo "<table><tr><td> $key : </td><td>$value</td></tr>
    }
 

and i get this notice

Notice: Unknown: Skipping numeric key 0. in Unknown on line 0
 

of course I start the session etc.
Thnx.

[djpaul]

Hi, I'm trying to create a session array and give a dynamic name.

I tried something like this but I get only the last entry i made (key=0) :

    $qid = $_POST['pstq'];
        $_SESSION[$qid] = array();
 
    foreach ($_SESSION[$qid] as $key=>$value) {
    echo "<table><tr><td> $key : </td><td>$value</td></tr>
    }
 

and i get this notice

Notice: Unknown: Skipping numeric key 0. in Unknown on line 0
 

of course I start the session etc.
Thnx.

But then different:
[PHP]
$qid = $_POST['pstq'];

$_SESSION['qid'] = $qid
[/PHP]

Because the super global is already some kind of array.
I used it to for my site and added some vaibles as email, status and so on.
Good luck!

Paul

[Atli]

Hi, I'm trying to create a session array and give a dynamic name.

I tried something like this but I get only the last entry i made (key=0) :

    $qid = $_POST['pstq'];
        $_SESSION[$qid] = array();
 
    foreach ($_SESSION[$qid] as $key=>$value) {
    echo "<table><tr><td> $key : </td><td>$value</td></tr>
    }
 

and i get this notice

Notice: Unknown: Skipping numeric key 0. in Unknown on line 0
 

of course I start the session etc.
Thnx.

Hi. Welcome to The Scripts!

The obvious error there is the missing quote-mark and semi-colon at the end of the echo statement. But, assuming that is a typo I would point out that your new $_SESSION[$qid] array is initialized each time you run the scripts as an empty array, which would presumably cause the foreach loop to be skipped entirely.

I can see no reason for the notice, however.

I did try something similar myself, which executed without warnings and gave me the results I expected:

<?php
    session_start();
 
    $qid = "pstg";
    $_SESSION[$qid] = array("one" => 1, 2 => "Two");
 
    echo "<pre>";
    print_r($_SESSION);
    echo "</pre>";
?>
 

[Hemo]

Hi, problem is bad key value of Session.
This code causes Notice

session_start(); 
$_SESSION["1"] = array('hodnota1');
 

This does not cause Notice

session_start(); 
$_SESSION["1a"] = array('hodnota1');
 

[lyodmichael]

are you trying to register a session, in a value of a textbox?