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Syntax error when using Password function in php and mysql

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I have the following code in my script and it's giving a syntax error at line *** when using the password function. My password in the mysql database is encrypted using the password function itself and I want to verify the input password against my database password. PLEASE HELP

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  1. if (isset($_POST["password"])) $password = @$_POST["password"];
  2.  
  3.  
  4.     if (($login != "") && ($password != "")) {
  5.       $conn = mysql_connect("localhost", "root", "root");
  6.       mysql_select_db("bnk_guarantee");
  7.       $sql = "select `Usr_Passwd` from `user` where `Usr_Login` = '" .$login ."'  and `Usr_Status` = 'Active' ";
  8.       $res = mysql_query($sql, $conn) or die(mysql_error());
  9.       $row = mysql_fetch_assoc($res) or $row = array(0 => "");;
  10.       if (isset($row)) reset($row);
  11. ***      $pass =password($password);
  12.       if (isset($password) && ($pass == trim(current($row)))) {
  13.         $_SESSION["logged_in"] = true;
  14.  
[Please use CODE tags when posting source code. Thanks! --pbmods]
Jun 14 '07 #1
2 1890
epots9
1,351 Recognized Expert Top Contributor
where is your password function?
Jun 14 '07 #2
pbmods
5,821 Recognized Expert Expert
There is no PHP password function. Try using sha1 or md5 instead.

[EDIT: Similar functions also exist in MySQL: http://dev.mysql.com/doc/refman/5.0/...functions.html]
Jun 14 '07 #3

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