On May 28, 1:05 pm, vinnie <centro.ga...@g mail.comwrote:
why i do not see anything but a blank page?
<?php
function somma($uno,$due )
{
$totale = $uno + $due;
return($totale) ;
}
$sum = somma(3,4);
$totale = $resto;
print("$resto") ;
print("$totale" );
?>
First things first: use a code formatting style that is easier to
read. Visit
http://en.wikipedia.org/wiki/Prettyprint to learn more.
<code>
// I like C-style
<h4>Test of somma function</h4>
<p>
<?php
function somma($uno,$due ) {
$totale = $uno + $due;
return $totale;
}
$sum = somma(3,4);
$totale = $sum; // Here, this was $resto, which is not pre-assigned a
value
print($resto); // Before, printed nothing, since $resto did not point
to anything
print($totale); // Before, a pointer to nothing ($resto)
?>
</p>
</code>
The error may be a scoping issue, an error in naming a variable, or
both. However, php is doing what is expected.
Since $totale is in a function where it is assigned a value, it is
considered "in the scope of the function" and is not available to the
global-space variable declaration. To make it accessible, you have to
import the global $variable:
<code>
function somma($uno,$due ) {
global $totale;
// continue code with $totale available
}
</code>
You can also pass by reference:
<code>
function somma($uno, $due, &$totale) { // <-- Notice ampersand (&)
$totale = $uno + $due;
return($totale) ;
}
</code>
But then, somewhat inexplicably, you assign $totale to a non-declared
$sum variable (which will make $totale === null), and then try to
print both.
Note how I put a page title and a horizontal rule (<hr />) tag before
and after the code I expect to output for testing. This tells me if
the page died on parse (one kind of error, like not escaping a
sequence correctly), if the page died on processing (like calling a
function that doesn't exist), or if, in this case, the code has
nothing to output. This helps troubleshoot the code more efficiently
and effectively.
