Hi All,
Please accept my appologies in advance for what I expect will be a
reasonably simple question.
I have an html form (which is generated in php) which contains a
number of rows (one row per product in the 'products' table).
It is generated with the following php
<code>
// create a table for the results
echo('<table border=1 cellpadding=2>' );
echo('<tr> <th>Product Description</th><th>Sales $</th><th>Sales
Units</th><th>Credits $</th><th>Credits Units</th> </tr>');
// add the results to the table
while ( $row = mysql_fetch_arr ay($result) ) {
// get columns from the output on the current row
$ProdDesc = $row['ProductDescrip tion'];
$ProdID = $row['ID'];
// write content collected above into table cells
echo('<tr><td>' );
echo($ProdDesc) ;
echo('</td><td>');
echo('<form action="update-db.php" method="post">< input type="text"
name="sd');
echo($ProdID);
echo('">');
echo('</td><td>');
echo('<form action="update-db.php" method="post">< input type="text"
name="su');
echo($ProdID);
echo('">');
echo('</td><td>');
echo('<form action="update-db.php" method="post">< input type="text"
name="cd');
echo($ProdID);
echo('">');
echo('</td><td>');
echo('<form action="update-db.php" method="post">< input type="text"
name="cu');
echo($ProdID);
echo('">');
echo('</td></tr>');
}
echo('</table>');
//the table is complete
</code>
The values sd1, su1, cd1, cu1,...... cuXX are all available to the
update-db.php page which is called when this form is submitted so I am
fairly sure this is working correctly.
So far, so good, but when it comes to inserting the data into the
database I have not been able to create the SQL dynamically (in
testing I know the number of products and have manually written lots
of SQL INSERTs but this will not work in the real world)
The SQL needs to look like roughly like this:
mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID,
WeekCommencing, Sales, Credits) VALUES ('',
'$prodID','$Wee kCommencing','$ sd1', '$cd1')");
My logic was to say something like this (which needless to say doesn't
work !)
<?php
for ($prodID = 1; $prodID <= $prodCount; $prodID++)
{
$currentSD = "sd" . $prodID
$currentSU = "su" . $prodID
$currentCD = "cd" . $prodID
$currentCU = "cu" . $prodID
mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID,
WeekCommencing, Sales, Credits) VALUES ('',
'$prodID','$Wee kCommencing','$ currentSD', '$currentCD')") ;
}
I may have messed up the for loop here but the real problem was that
query would insert '$sd1', '$sd2' etc as text strings into the
database rather than evaluating $sd1 to it's value (passed from the
original table which would be a number)
I have tried using eval() with no success (though that may well be due
to my complete newbieness with php). I have also tried passing the
values from the original html as arrays and trying to use simillar
logic as above to read from $array[$currentArrayEl ement] also with no
success. Again, if I manually echo the results of $array[0] I am
returned the value entered in the first html field but I can not
dynamically select the next array element.
I hope I have made sense of the problem without writing unnecessary
garbage.
Many thanks in advance for your assistance.
Dave Nouwens
Sydney, Australia. 3 2111
Dave Nouwens wrote: I have an html form (which is generated in php) which contains a number of rows (one row per product in the 'products' table).
It is generated with the following php
<code> // create a table for the results echo('<table border=1 cellpadding=2>' ); echo('<tr> <th>Product Description</th><th>Sales $</th><th>Sales Units</th><th>Credits $</th><th>Credits Units</th> </tr>');
// add the results to the table while ( $row = mysql_fetch_arr ay($result) ) { // get columns from the output on the current row $ProdDesc = $row['ProductDescrip tion']; $ProdID = $row['ID']; // write content collected above into table cells echo('<tr><td>' ); echo($ProdDesc) ; echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="sd'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="su'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="cd'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="cu'); echo($ProdID); echo('">'); echo('</td></tr>'); } echo('</table>'); //the table is complete </code>
I think your problem is right there, in the HTML.
<form>s do not nest!
If you have several <form>s in your page the posted data is the contents
of just one of them.
I usually do <form>s and <table>s like this:
<form>
<table>
<tr>
<td>...</td>
<td><input ...></td>
</tr>
<tr>
<td>...</td>
<td><input ...></td>
</tr>
</table>
</form>
The values sd1, su1, cd1, cu1,...... cuXX are all available to the update-db.php page which is called when this form is submitted so I am fairly sure this is working correctly.
Hmmm ... maybe I'm wrong :)
So far, so good, but when it comes to inserting the data into the database I have not been able to create the SQL dynamically (in testing I know the number of products and have manually written lots of SQL INSERTs but this will not work in the real world)
The SQL needs to look like roughly like this: mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID, WeekCommencing, Sales, Credits) VALUES ('', '$prodID','$Wee kCommencing','$ sd1', '$cd1')");
My logic was to say something like this (which needless to say doesn't work !) <?php
for ($prodID = 1; $prodID <= $prodCount; $prodID++) { $currentSD = "sd" . $prodID $currentSU = "su" . $prodID $currentCD = "cd" . $prodID $currentCU = "cu" . $prodID
mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID, WeekCommencing, Sales, Credits) VALUES ('', '$prodID','$Wee kCommencing','$ currentSD', '$currentCD')") ; }
I may have messed up the for loop here but the real problem was that query would insert '$sd1', '$sd2' etc as text strings into the database rather than evaluating $sd1 to it's value (passed from the original table which would be a number)
Try variable variables http://www.php.net/manual/en/languag...s.variable.php
$currentSD = ${'sd' . $prodID};
If you turn register_global s off (which might be a good idea) change
that line to
$currentSD = $_POST['sd' . $prodID];
I have tried using eval() with no success (though that may well be due to my complete newbieness with php). I have also tried passing the values from the original html as arrays and trying to use simillar logic as above to read from $array[$currentArrayEl ement] also with no success. Again, if I manually echo the results of $array[0] I am returned the value entered in the first html field but I can not dynamically select the next array element.
Happy Coding :)
--
USENET would be a better place if everybody read: : mail address : http://www.catb.org/~esr/faqs/smart-questions.html : is valid for : http://www.netmeister.org/news/learn2quote2.html : "text/plain" : http://www.expita.com/nomime.html : to 10K bytes :
Dave Nouwens wrote: Hi All,
Please accept my appologies in advance for what I expect will be a reasonably simple question.
I have an html form (which is generated in php) which contains a number of rows (one row per product in the 'products' table).
It is generated with the following php
<code> // create a table for the results echo('<table border=1 cellpadding=2>' ); echo('<tr> <th>Product Description</th><th>Sales $</th><th>Sales Units</th><th>Credits $</th><th>Credits Units</th> </tr>');
// add the results to the table while ( $row = mysql_fetch_arr ay($result) ) { // get columns from the output on the current row $ProdDesc = $row['ProductDescrip tion']; $ProdID = $row['ID']; // write content collected above into table cells echo('<tr><td>' ); echo($ProdDesc) ; echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="sd'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="su'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="cd'); echo($ProdID); echo('">'); echo('</td><td>'); echo('<form action="update-db.php" method="post">< input type="text" name="cu'); echo($ProdID); echo('">'); echo('</td></tr>'); } echo('</table>'); //the table is complete </code>
The values sd1, su1, cd1, cu1,...... cuXX are all available to the update-db.php page which is called when this form is submitted so I am fairly sure this is working correctly.
So far, so good, but when it comes to inserting the data into the database I have not been able to create the SQL dynamically (in testing I know the number of products and have manually written lots of SQL INSERTs but this will not work in the real world)
The SQL needs to look like roughly like this: mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID, WeekCommencing, Sales, Credits) VALUES ('', '$prodID','$Wee kCommencing','$ sd1', '$cd1')");
My logic was to say something like this (which needless to say doesn't work !) <?php
for ($prodID = 1; $prodID <= $prodCount; $prodID++) { $currentSD = "sd" . $prodID $currentSU = "su" . $prodID $currentCD = "cd" . $prodID $currentCU = "cu" . $prodID
mysql_query ("INSERT INTO sales_dollars (SaleID, ProductID, WeekCommencing, Sales, Credits) VALUES ('', '$prodID','$Wee kCommencing','$ currentSD', '$currentCD')") ; }
I may have messed up the for loop here but the real problem was that query would insert '$sd1', '$sd2' etc as text strings into the database rather than evaluating $sd1 to it's value (passed from the original table which would be a number)
I have tried using eval() with no success (though that may well be due to my complete newbieness with php). I have also tried passing the values from the original html as arrays and trying to use simillar logic as above to read from $array[$currentArrayEl ement] also with no success. Again, if I manually echo the results of $array[0] I am returned the value entered in the first html field but I can not dynamically select the next array element.
I hope I have made sense of the problem without writing unnecessary garbage.
Many thanks in advance for your assistance.
Dave Nouwens Sydney, Australia.
Variable variables can be evaluated thus:
$currentSD = ${"sd".$prodID} ;
$currentSU = ${"su".$prodID} ;
$currentCD = ${"cd".$prodID} ;
$currentCU = ${"cu".$prodID} ;
It may also be a case of evaluating the SQL string before passing to
mysql_query():
$sqlInsert = "INSERT INTO sales_dollars (SaleID, ProductID,
WeekCommencing, Sales, Credits) VALUES ('',
'".$prodID."',' ".$WeekCommenci ng."','".$curre ntSD."', '".$currentCD." ')";
mysql_query($sq lInsert);
Hope this helps.
===
Michael S. Clark
Web Applications Developer
Scotland On Line
"Michael S. Clark" <mc****@scotlan donline.co.uk> wrote in message news:<c9******* ***@phys-pa.scotland.net >...
--8<--8<--8< Hope this helps.
=== Michael S. Clark Web Applications Developer Scotland On Line
It helped tremendously, thankyou (and thanks also to Pedro for getting
it started in the right direction)
Dave This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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