ok i decided to take Erwin Moller and start a fresh topic and im taking a different approach

[so many sites so little time]

this time i am going to use the scripts from the book and just change
the names to match what i am trying to do now i just got an error that
i know shouldnt be an error i think. this is the error:

Could add the site entry because: Column count doesn't match value
count at row 1. The query was INSERT INTO home (home_id, header, body,
date_entered) VALUES ('Welcome!', 'What is a Progressive Parent? A
Progressive Parent ...

now i created the table using what the book gave me which is:

// Define the query.
$query = 'CREATE TABLE home (
home_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
header VARCHAR(100) NOT NULL,
body TEXT NOT NULL,
date_entered DATETIME NOT NULL
)';

// Run the query.
if (@mysql_query ($query)) {
print '<p>The table has been created.</p>';
} else {
die ('<p>Could not create the table because: <b>' . mysql_error() .
'</b>.</p><p>The query being run was: ' . $query . '</p>');
}

and when i ran that script live i got the message "The table has been
created."

now when i run this script and try to insert the data is when i get the
error message i posted above and that script looks like:

// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

// Execute the query.
if (@mysql_query ($query)) {
print '<p>The site entry has been added.</p>';
} else {
print "<p>Could add the site entry because: <b>" . mysql_error() .
"</b>. The query was $query.</p>";
}

mysql_close();

}

// Display the form.
?>
<form action="edit_si te.php" method="post">
<p>Entry Title: <input type="text" name="header" size="40"
maxsize="100" /></p>
<p>Entry Text: <textarea name="body" cols="40" rows="5"></textarea></p>
<input type="submit" name="submit" value="Add to the Site" />
</form>

[so many sites so little time]

to me it looks like the dateentered and the home id arent being entered
into the database correct?
so many sites so little time wrote:

this time i am going to use the scripts from the book and just change
the names to match what i am trying to do now i just got an error that
i know shouldnt be an error i think. this is the error:

Could add the site entry because: Column count doesn't match value
count at row 1. The query was INSERT INTO home (home_id, header, body,
date_entered) VALUES ('Welcome!', 'What is a Progressive Parent? A
Progressive Parent ...

now i created the table using what the book gave me which is:

// Define the query.
$query = 'CREATE TABLE home (
home_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
header VARCHAR(100) NOT NULL,
body TEXT NOT NULL,
date_entered DATETIME NOT NULL
)';

// Run the query.
if (@mysql_query ($query)) {
print '<p>The table has been created.</p>';
} else {
die ('<p>Could not create the table because: <b>' . mysql_error() .
'</b>.</p><p>The query being run was: ' . $query . '</p>');
}

and when i ran that script live i got the message "The table has been
created."

now when i run this script and try to insert the data is when i get the
error message i posted above and that script looks like:

// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

// Execute the query.
if (@mysql_query ($query)) {
print '<p>The site entry has been added.</p>';
} else {
print "<p>Could add the site entry because: <b>" . mysql_error() .
"</b>. The query was $query.</p>";
}

mysql_close();

}

// Display the form.
?>
<form action="edit_si te.php" method="post">
<p>Entry Title: <input type="text" name="header" size="40"
maxsize="100" /></p>
<p>Entry Text: <textarea name="body" cols="40" rows="5"></textarea></p>
<input type="submit" name="submit" value="Add to the Site" />
</form>

[so many sites so little time]

this is the print out from phpmyadmin if you have used that before this
might help you understand the structure of the table

home:
Field Type Null Default
home_id int(10) No
header varchar(100) No
body text No
date_entered datetime No 0000-00-00 00:00:00
Indexes:
Keyname Type Cardinality Field
PRIMARY PRIMARY 0 home_id
Space usage:
Type Usage
Data 0 B
Index 1,024 B
Total 1,024 B

Row Statistics:
Statements Value
Format dynamic
Rows 0
Next Autoindex 1
Creation Nov 19, 2006 at 10:43 AM
Last update Nov 19, 2006 at 10:43 AM

so many sites so little time wrote:

to me it looks like the dateentered and the home id arent being entered
into the database correct?
so many sites so little time wrote:

this time i am going to use the scripts from the book and just change
the names to match what i am trying to do now i just got an error that
i know shouldnt be an error i think. this is the error:

Could add the site entry because: Column count doesn't match value
count at row 1. The query was INSERT INTO home (home_id, header, body,
date_entered) VALUES ('Welcome!', 'What is a Progressive Parent? A
Progressive Parent ...

now i created the table using what the book gave me which is:

// Define the query.
$query = 'CREATE TABLE home (
home_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
header VARCHAR(100) NOT NULL,
body TEXT NOT NULL,
date_entered DATETIME NOT NULL
)';

// Run the query.
if (@mysql_query ($query)) {
print '<p>The table has been created.</p>';
} else {
die ('<p>Could not create the table because: <b>' . mysql_error() .
'</b>.</p><p>The query being run was: ' . $query . '</p>');
}

and when i ran that script live i got the message "The table has been
created."

now when i run this script and try to insert the data is when i get the
error message i posted above and that script looks like:

// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

// Execute the query.
if (@mysql_query ($query)) {
print '<p>The site entry has been added.</p>';
} else {
print "<p>Could add the site entry because: <b>" . mysql_error() .
"</b>. The query was $query.</p>";
}

mysql_close();

}

// Display the form.
?>
<form action="edit_si te.php" method="post">
<p>Entry Title: <input type="text" name="header" size="40"
maxsize="100" /></p>
<p>Entry Text: <textarea name="body" cols="40" rows="5"></textarea></p>
<input type="submit" name="submit" value="Add to the Site" />
</form>

[Norman Peelman]

"so many sites so little time" <kk*****@gmail. comwrote in message
news:11******** **************@ m73g2000cwd.goo glegroups.com.. .

this time i am going to use the scripts from the book and just change
the names to match what i am trying to do now i just got an error that
i know shouldnt be an error i think. this is the error:

Could add the site entry because: Column count doesn't match value
count at row 1. The query was INSERT INTO home (home_id, header, body,
date_entered) VALUES ('Welcome!', 'What is a Progressive Parent? A
Progressive Parent ...

now i created the table using what the book gave me which is:

// Define the query.
$query = 'CREATE TABLE home (
home_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
header VARCHAR(100) NOT NULL,
body TEXT NOT NULL,
date_entered DATETIME NOT NULL
)';

// Run the query.
if (@mysql_query ($query)) {
print '<p>The table has been created.</p>';
} else {
die ('<p>Could not create the table because: <b>' . mysql_error() .
'</b>.</p><p>The query being run was: ' . $query . '</p>');
}

and when i ran that script live i got the message "The table has been
created."

now when i run this script and try to insert the data is when i get the
error message i posted above and that script looks like:

// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

// Execute the query.
if (@mysql_query ($query)) {
print '<p>The site entry has been added.</p>';
} else {
print "<p>Could add the site entry because: <b>" . mysql_error() .
"</b>. The query was $query.</p>";
}

mysql_close();

}

First problem is you are not entering your home_id at all (it takes a 0 -
zero or a NULL to work), make your $query look like this:

$query = "INSERT INTO home (home_id, header, body, date_entered) VALUES
(NULL,'{$_POST['header']}', '{$_POST['body']}', NOW())";

....and second (and personal taste) is if you aren't using multi-dimensional
arrays you can do it this way:

$query = "INSERT INTO home (home_id, header, body, date_entered) VALUES
(NULL,'$_POST[header]', '$_POST[body]', NOW())";

// Display the form.
?>
<form action="edit_si te.php" method="post">
<p>Entry Title: <input type="text" name="header" size="40"
maxsize="100" /></p>
<p>Entry Text: <textarea name="body" cols="40" rows="5"></textarea></p>
<input type="submit" name="submit" value="Add to the Site" />
</form>

Norm
--
FREE Avatar hosting at www.easyavatar.com

[Jerry Stuckle]

Norman Peelman wrote:

"so many sites so little time" <kk*****@gmail. comwrote in message
news:11******** **************@ m73g2000cwd.goo glegroups.com.. .

>>this time i am going to use the scripts from the book and just change
the names to match what i am trying to do now i just got an error that
i know shouldnt be an error i think. this is the error:

Could add the site entry because: Column count doesn't match value
count at row 1. The query was INSERT INTO home (home_id, header, body,
date_entere d) VALUES ('Welcome!', 'What is a Progressive Parent? A
Progressive Parent ...

now i created the table using what the book gave me which is:

// Define the query.
$query = 'CREATE TABLE home (
home_id INT UNSIGNED NOT NULL AUTO_INCREMENT PRIMARY KEY,
header VARCHAR(100) NOT NULL,
body TEXT NOT NULL,
date_entere d DATETIME NOT NULL
)';

// Run the query.
if (@mysql_query ($query)) {
print '<p>The table has been created.</p>';
} else {
die ('<p>Could not create the table because: <b>' . mysql_error() .
'</b>.</p><p>The query being run was: ' . $query . '</p>');
}

and when i ran that script live i got the message "The table has been
created."

now when i run this script and try to insert the data is when i get the
error message i posted above and that script looks like:

// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

// Execute the query.
if (@mysql_query ($query)) {
print '<p>The site entry has been added.</p>';
} else {
print "<p>Could add the site entry because: <b>" . mysql_error() .
"</b>. The query was $query.</p>";
}

mysql_close() ;

}

First problem is you are not entering your home_id at all (it takes a 0 -
zero or a NULL to work), make your $query look like this:

Incorrect. It is perfectly valid to not enter home_id in the INSERT
statement. The autonum value will be used.

$query = "INSERT INTO home (home_id, header, body, date_entered) VALUES
(NULL,'{$_POST['header']}', '{$_POST['body']}', NOW())";

This will also work, but is not necessary.

...and second (and personal taste) is if you aren't using multi-dimensional
arrays you can do it this way:

$query = "INSERT INTO home (home_id, header, body, date_entered) VALUES
(NULL,'$_POST[header]', '$_POST[body]', NOW())";

Additionally, you should never use data entered by the user without
validating it. Additionally, any data entered should be processed by
mysql_real_esca pe_string() before placing in the database.

>

>>// Display the form.
?>
<form action="edit_si te.php" method="post">
<p>Entry Title: <input type="text" name="header" size="40"
maxsize="10 0" /></p>
<p>Entry Text: <textarea name="body" cols="40" rows="5"></textarea></p>
<input type="submit" name="submit" value="Add to the Site" />
</form>

Norm

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attgl obal.net
=============== ===

[Pedro Graca]

Jerry Stuckle wrote:

Norman Peelman wrote:

>"so many sites so little time" <kk*****@gmail. comwrote in message
news:11******* *************** @m73g2000cwd.go oglegroups.com. ..

>>>// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)

^==1==^ ^==2=^ ^=3^ ^=====4====^

>>>VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

^=========1==== ====^ ^========2===== ==^ ^=3=^

ERROR 1136 (21S01): Column count doesn't match value count ...

4 columns (home_id, header, body, and date_entered) and 3 values give
the error 1136 in my MySQL (v 4.1.10)

>First problem is you are not entering your home_id at all (it takes a 0 -
zero or a NULL to work), make your $query look like this:

Incorrect. It is perfectly valid to not enter home_id in the INSERT
statement. The autonum value will be used.

I agree with Norm :)
The SQL statement from "so many sites so little time" generates an
error.

The only way to make it valid is to eliminate it from the column
specification:

$query = "INSERT INTO home (header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

--
I (almost) never check the dodgeit address.
If you *really* need to mail me, use the address in the Reply-To
header with a message in *plain* *text* *without* *attachments*.

[so many sites so little time]

thanks so much for all the help im going to remove the home_id if that
doesnt work i am going to make it null all i am really trying to achive
in the end is a page where a client could enter that they would like
text on their site to be and update the database with that text and a
script that would display that text. i went out tonight and bought
another php book its the php phrasebook by chris wenz. i have quite a
few books on php and or mysql 4 to be exact and none of them really got
what i needed for this through to my head but tonight a sat at borders
with a cup of coffee and read through the section on inserting and
displaying data from a mysql database from the sections of every single
php, and php and mysql book that they had in stock and took notes so i
should be golden if there are anymore problems or errors with this i
will let you guys know so you can be of help and that you all for
helping so much you are all really good people for taking the time to
help me out. : )
Pedro Graca wrote:

Jerry Stuckle wrote:

Norman Peelman wrote:

"so many sites so little time" <kk*****@gmail. comwrote in message
news:11******** **************@ m73g2000cwd.goo glegroups.com.. .
// Define the query.
$query = "INSERT INTO home (home_id, header, body, date_entered)

^==1==^ ^==2=^ ^=3^ ^=====4====^

>>VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

^=========1==== ====^ ^========2===== ==^ ^=3=^

ERROR 1136 (21S01): Column count doesn't match value count ...

4 columns (home_id, header, body, and date_entered) and 3 values give
the error 1136 in my MySQL (v 4.1.10)

First problem is you are not entering your home_id at all (it takes a 0 -
zero or a NULL to work), make your $query look like this:

Incorrect. It is perfectly valid to not enter home_id in the INSERT
statement. The autonum value will be used.

I agree with Norm :)
The SQL statement from "so many sites so little time" generates an
error.

The only way to make it valid is to eliminate it from the column
specification:

$query = "INSERT INTO home (header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

--
I (almost) never check the dodgeit address.
If you *really* need to mail me, use the address in the Reply-To
header with a message in *plain* *text* *without* *attachments*.

[Jerry Stuckle]

so many sites so little time wrote:

thanks so much for all the help im going to remove the home_id if that
doesnt work i am going to make it null all i am really trying to achive
in the end is a page where a client could enter that they would like
text on their site to be and update the database with that text and a
script that would display that text. i went out tonight and bought
another php book its the php phrasebook by chris wenz. i have quite a
few books on php and or mysql 4 to be exact and none of them really got
what i needed for this through to my head but tonight a sat at borders
with a cup of coffee and read through the section on inserting and
displaying data from a mysql database from the sections of every single
php, and php and mysql book that they had in stock and took notes so i
should be golden if there are anymore problems or errors with this i
will let you guys know so you can be of help and that you all for
helping so much you are all really good people for taking the time to
help me out. : )
Pedro Graca wrote:

>>Jerry Stuckle wrote:

>>>Norman Peelman wrote:

"so many sites so little time" <kk*****@gmail. comwrote in message
news:11**** *************** ***@m73g2000cwd .googlegroups.c om...

>// Define the query.
>$query = "INSERT INTO home (home_id, header, body, date_entered)

^==1==^ ^==2=^ ^=3^ ^=====4====^

>>>>>VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

^=========1==== ====^ ^========2===== ==^ ^=3=^

ERROR 1136 (21S01): Column count doesn't match value count ...

4 columns (home_id, header, body, and date_entered) and 3 values give
the error 1136 in my MySQL (v 4.1.10)

>>>>First problem is you are not entering your home_id at all (it takes a 0 -
zero or a NULL to work), make your $query look like this:

Incorrect. It is perfectly valid to not enter home_id in the INSERT
statement. The autonum value will be used.

I agree with Norm :)
The SQL statement from "so many sites so little time" generates an
error.

The only way to make it valid is to eliminate it from the column
specification :

$query = "INSERT INTO home (header, body, date_entered)
VALUES ('{$_POST['header']}', '{$_POST['body']}', NOW())";

--
I (almost) never check the dodgeit address.
If you *really* need to mail me, use the address in the Reply-To
header with a message in *plain* *text* *without* *attachments*.

While you're at it, please buy a book on how to post to usenet. You're
making things much harder on yourself in the way you're posting.

If you were posting properly you would get a lot more responses to your
messages.

--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
js*******@attgl obal.net
=============== ===

[Erwin Moller]

so many sites so little time wrote:

<snip>

You took ME?
Woot, I completely missed that. :P

Erwin Moller