if I code
$birth = strtotime('1 April 1950');
then $birth = -1, I guess that this is because time "began" on 1st Jan,
1970. (although I seem to remember a few good times before that).
So, what's the easiest way to find out how many days old I am (exactly,
please, not just taking 1 April 1970 and adding 20 *365, which does not
account for leap years?)
Thanks in advance.
2  2989 
Baron Samedi schrieb:
if I code
$birth = strtotime('1 April 1950');
then $birth = -1, I guess that this is because time "began" on 1st Jan,
1970. (although I seem to remember a few good times before that).
So, what's the easiest way to find out how many days old I am (exactly,
please, not just taking 1 April 1970 and adding 20 *365, which does not
account for leap years?)
Thanks in advance.
Have a look at the safestrtotime() function suggested in the user
contributed notes in the PHP manual: http://ch2.php.net/manual/de/functio...time.php#54564
HTH
Markus
Markus Ernst wrote:
Baron Samedi schrieb:
if I code
$birth = strtotime('1 April 1950');
then $birth = -1, I guess that this is because time "began" on 1st Jan,
1970. (although I seem to remember a few good times before that).
So, what's the easiest way to find out how many days old I am (exactly,
please, not just taking 1 April 1970 and adding 20 *365, which does not
account for leap years?)
Thanks in advance.
Have a look at the safestrtotime() function suggested in the user
contributed notes in the PHP manual:
http://ch2.php.net/manual/de/functio...time.php#54564
Thanks, that wokred a treat! This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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