I keep getting this error in in_array. Any ideas why?

[rich]

I keep getting the error:
Warning: in_array(): Wrong datatype for second argument on line 679
here is the code.
I declare and fill the array
$specprimA = array();
$specprimA= getspecprim($dr esstypeid);
$primsecA=getpr imsec();

Then I do a compare using in Array. I even put in the extra step of
making sure I have something in the array with the is sizeof statement.

$numcl= count($primsecA );
for ($i=0; $i<$numcl; $i++){
$primsec = $primsecA[$i]['primsec'];
if (sizeof($specpr imA) >0){
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
<input type="checkbox" checked tabindex="2" name="primsecid[]"
value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
$primsec;
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
}?>

This is line 679
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>

Any ideas why?

[rich]

Oh here is the getspecprim() function

function getspecprim($dr esstypeid) {
$getQ="SELECT primsecid FROM li_dresstypepsp
WHERE
dresstypeid= '$dresstypeid'" ;
$getR = pg_query($getQ) ;
$getA= pg_fetch_all($g etR);
return($getA);
}

rich wrote:

I keep getting the error:
Warning: in_array(): Wrong datatype for second argument on line 679
here is the code.
I declare and fill the array
$specprimA = array();
$specprimA= getspecprim($dr esstypeid);
$primsecA=getpr imsec();

Then I do a compare using in Array. I even put in the extra step of
making sure I have something in the array with the is sizeof statement.

$numcl= count($primsecA );
for ($i=0; $i<$numcl; $i++){
$primsec = $primsecA[$i]['primsec'];
if (sizeof($specpr imA) >0){
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
<input type="checkbox" checked tabindex="2" name="primsecid[]"
value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
$primsec;
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
}?>

This is line 679
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>

Any ideas why?

[Juliette]

rich wrote:

Oh here is the getspecprim() function

function getspecprim($dr esstypeid) {
$getQ="SELECT primsecid FROM li_dresstypepsp
WHERE
dresstypeid= '$dresstypeid'" ;
$getR = pg_query($getQ) ;
$getA= pg_fetch_all($g etR);
return($getA);
}

rich wrote:

>I keep getting the error:
Warning: in_array(): Wrong datatype for second argument on line 679
here is the code.
I declare and fill the array
$specprimA = array();
$specprimA= getspecprim($dr esstypeid);
$primsecA=getp rimsec();

Then I do a compare using in Array. I even put in the extra step of
making sure I have something in the array with the is sizeof statement.

$numcl= count($primsecA );
for ($i=0; $i<$numcl; $i++){
$primsec = $primsecA[$i]['primsec'];
if (sizeof($specpr imA) >0){
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
<input type="checkbox" checked tabindex="2" name="primsecid[]"
value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
$primsec;
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
}?>

This is line 679
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>

Any ideas why?

count / sizeof on a boolean or string will return 1, so try changing the
line above the problem line to:
if( is_array( $specprimA ) && count( $specprimA ) 0 ) {

Alternatively, IMHO a better solution, would be to do the checking /
typecasting in the function.

replace:
return($getA);

with something along the lines of:
if( !is_array( $getA ) {
return array();
}
else {
return $getA;
}

[rich]

Juliette that was a good idea. Thanks.

Juliette wrote:

rich wrote:

Oh here is the getspecprim() function

function getspecprim($dr esstypeid) {
$getQ="SELECT primsecid FROM li_dresstypepsp
WHERE
dresstypeid= '$dresstypeid'" ;
$getR = pg_query($getQ) ;
$getA= pg_fetch_all($g etR);
return($getA);
}

rich wrote:

I keep getting the error:
Warning: in_array(): Wrong datatype for second argument on line 679
here is the code.
I declare and fill the array
$specprimA = array();
$specprimA= getspecprim($dr esstypeid);
$primsecA=getpr imsec();

Then I do a compare using in Array. I even put in the extra step of
making sure I have something in the array with the is sizeof statement.

$numcl= count($primsecA );
for ($i=0; $i<$numcl; $i++){
$primsec = $primsecA[$i]['primsec'];
if (sizeof($specpr imA) >0){
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>
<input type="checkbox" checked tabindex="2" name="primsecid[]"
value="<?php echo $primsecA[$i]['primsecid']; ?>"/><?php echo
$primsec;
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
} else { ?>
<input type="checkbox" tabindex="2" name="primsecid[]" value="<?php
echo $primsecA[$i]['primsecid']; ?>"/><?php echo $primsec;
}
}?>

This is line 679
if (in_array($prim secA[$i]['primsecid'], $specprimA)) { ?>

Any ideas why?

count / sizeof on a boolean or string will return 1, so try changing the
line above the problem line to:
if( is_array( $specprimA ) && count( $specprimA ) 0 ) {

Alternatively, IMHO a better solution, would be to do the checking /
typecasting in the function.

replace:
return($getA);

with something along the lines of:
if( !is_array( $getA ) {
return array();
}
else {
return $getA;
}