Concatenate string and variable to make up a constant name

[Peter]

Hi,

I know that it is possible to build up a variable name based on a
string and another variable name i.e.

$varnum=5;
${"varnumber_$v arnum"} = 'This variable should be called varnumber_5';

but is it possible to do this for a constant? For example I may have
constants set up as

define('CONSTNU MBER_1', 'This is constantnumber 1');
define('CONSTNU MBER_2', 'This is constantnumber 2');
define('CONSTNU MBER_3', 'This is constantnumber 3');

and I may want to access them from inside a loop i.e.

for($counter=1; $counter<=3; $counter}}) {
echo 'Contents of current constant = ' . ${"CONSTNUMBER_ $counter"} ;
}

Now obviously this doesn't work because it sees
${"CONSTNUMBER_ $counter"} as a variable but if I try and take the $
off then I just get errors.

Can anyone help? Does this even make sense? :-)

[Peter]

Peter wrote:

Hi,

I know that it is possible to build up a variable name based on a
string and another variable name i.e.

$varnum=5;
${"varnumber_$v arnum"} = 'This variable should be called varnumber_5';

but is it possible to do this for a constant? For example I may have
constants set up as

define('CONSTNU MBER_1', 'This is constantnumber 1');
define('CONSTNU MBER_2', 'This is constantnumber 2');
define('CONSTNU MBER_3', 'This is constantnumber 3');

and I may want to access them from inside a loop i.e.

for($counter=1; $counter<=3; $counter}}) {
echo 'Contents of current constant = ' . ${"CONSTNUMBER_ $counter"} ;
}

Now obviously this doesn't work because it sees
${"CONSTNUMBER_ $counter"} as a variable but if I try and take the $
off then I just get errors.

Can anyone help? Does this even make sense? :-)

Typically I've just found the answer. I just build up a string of the
constant name and then wrap the constant function around it.

Obviously I was overcomplicatin g things. Ah well.