I would like to display error messages put out by shell commands. For
example the following code gives no output and the array $output has no
values:
<?php
exec( 'lss', $output );
var_dump( $output );
?>
...assuming that I don't have an executable called 'lss' on my computer.
The equivalent on the command line displays the error message:
# php -r 'exec( "lss", $output );'
# sh: lss: command not found
How do I get the exec() command to display errors?
I've tried `exec( 'lss 2/dev/stout', $output );' with no success. 3 14904
Robert S schreef:
I would like to display error messages put out by shell commands. For
example the following code gives no output and the array $output has no
values:
<?php
exec( 'lss', $output );
var_dump( $output );
?>
How about just:
<?php
$strRawOutput = exec( 'lss', $output );
var_dump($strRa wOutput);
?>
This only retrieves the last output line though. If you need more then
you should use passthru() instead of exec().
HTH,
Peter.
-- http://www.phpforums.nl
How about just:
<?php
$strRawOutput = exec( 'lss', $output );
var_dump($strRa wOutput);
?>
This still doesn't print the error message. It only prints whatever is
directed to stdout.
Robert S wrote:
I would like to display error messages put out by shell commands. For
example the following code gives no output and the array $output has no
values:
<?php
exec( 'lss', $output );
var_dump( $output );
?>
..assuming that I don't have an executable called 'lss' on my computer.
The equivalent on the command line displays the error message:
# php -r 'exec( "lss", $output );'
# sh: lss: command not found
How do I get the exec() command to display errors?
I've tried `exec( 'lss 2/dev/stout', $output );' with no success.
2redirection is a shell function, not the OS. You'll need to use
shell_exec() to allow the redirection.
Also, the syntax should be 2>&1. That way if stdout is also redirected
stderr will follow.
--
=============== ===
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Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
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