Retrieving an Image if Condition Not Met

[Pete]

I'm sure the answer is simple, but the solution is eluding me-I'm
not too good at the particulars of scripting. Maybe someone can point
me on the right path...

Here is the problem:

I have a string of php code that retrieves an image, in this case, an
image of a book cover from Amazon.com. This works perfectly well,
unless, there isn't an image of the book on Amazon's server. When
there's no image, a blank hole appears on the final page. What I
would like to happen is, if the variable for the image isn't met
(i.e. no book cover image), a "No Image" image, from my server,
will load in its place.

Here is the code that retrieves the image:

<img border="0" src=<? echo $i['ImageUrlSmall'];?>>

Is there a way to include a command that will retrieve an image from
http://www.mysite.com/images/noimage.gif if the first condition is not
met?

If anyone can help me, I'd be grateful.

--Pete

[Sandman]

In article <11************ *********@i40g2 000cwc.googlegr oups.com>,
"Pete" <ca******@gmail .com> wrote:

I'm sure the answer is simple, but the solution is eluding me-I'm
not too good at the particulars of scripting. Maybe someone can point
me on the right path...

Here is the problem:

I have a string of php code that retrieves an image, in this case, an
image of a book cover from Amazon.com. This works perfectly well,
unless, there isn't an image of the book on Amazon's server. When
there's no image, a blank hole appears on the final page. What I
would like to happen is, if the variable for the image isn't met
(i.e. no book cover image), a "No Image" image, from my server,
will load in its place.

Here is the code that retrieves the image:

<img border="0" src=<? echo $i['ImageUrlSmall'];?>>

Is there a way to include a command that will retrieve an image from
http://www.mysite.com/images/noimage.gif if the first condition is not
met?

If anyone can help me, I'd be grateful.

--Pete

<?
$image = $i['ImageUrlSmall'] ? $i['ImageUrlSmall'] : "noimage.gi f";
?>
<img src="<?=$image ?>" />

Cleaned it up so it's easier to read. You can do it this way as well:

<img border="0" src="<? echo $i['ImageUrlSmall'] ? $i['ImageUrlSmall']
: "noimage.gif";? >">
--
Sandman[.net]

[tim]

Pete wrote:

I'm sure the answer is simple, but the solution is eluding me-I'm
not too good at the particulars of scripting. Maybe someone can point
me on the right path...

Here is the problem:

I have a string of php code that retrieves an image, in this case, an
image of a book cover from Amazon.com. This works perfectly well,
unless, there isn't an image of the book on Amazon's server. When
there's no image, a blank hole appears on the final page. What I
would like to happen is, if the variable for the image isn't met
(i.e. no book cover image), a "No Image" image, from my server,
will load in its place.

Here is the code that retrieves the image:

<img border="0" src=<? echo $i['ImageUrlSmall'];?>>

Is there a way to include a command that will retrieve an image from
http://www.mysite.com/images/noimage.gif if the first condition is not
met?

If anyone can help me, I'd be grateful.

--Pete

The condition is whether the file exists on amazons server.

One way to do check this is send a HTTP Head request to amazon's server
for the file, if the status code in the response is 200 then the file
exists at that location.

The php manual page for fsockopen will help you do it

Tim