Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the total
pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
14  6601 
"dottty" <do****@noemail pls.met> wrote in message
news:44******** *************** @news.sunsite.d k... Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the
total pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
SELECT Count(dept) AS deptcount
FROM [table]
GROUP BY id
On Thu, 02 Mar 2006 11:41:12 +0800, dottty wrote: Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the total
pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
Blimey, is that sql? Given the standard rider about this *not* being a
mysql support group, something like the (untested) suggestion below might
help:
select dept, count(*), sum(pay) from ... group by dept, order by dept;
Steve
Hi,
Thanks for the prompt reply. However, i think it should be GROUP BY dept.
cheers
"Bosconian" <bo*******@plan etx.com> wrote in message
news:_p******** *************** *******@comcast .com... "dottty" <do****@noemail pls.met> wrote in message
news:44******** *************** @news.sunsite.d k... Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the
total pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
SELECT Count(dept) AS deptcount
FROM [table]
GROUP BY id
Hi Steve,
Thanks for the reply. It works.
i am aware that this is not a sql group, but i beg your indulgence, as i am
quite sure that you guys will respond,
because i believe that most folks who use PHP
will also be using mysql.
is that correct?
cheers
"Steve" <Th*****@Aint.V alid> wrote in message
news:pa******** *************** *****@Aint.Vali d... On Thu, 02 Mar 2006 11:41:12 +0800, dottty wrote:
Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the
total
pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
Blimey, is that sql? Given the standard rider about this *not* being a
mysql support group, something like the (untested) suggestion below might
help:
select dept, count(*), sum(pay) from ... group by dept, order by dept;
Steve
no.mail.pls wrote: Hi Steve,
Thanks for the reply. It works.
i am aware that this is not a sql group, but i beg your indulgence, as i am
quite sure that you guys will respond,
because i believe that most folks who use PHP
will also be using mysql.
is that correct?
cheers
"Steve" <Th*****@Aint.V alid> wrote in message
news:pa******** *************** *****@Aint.Vali d...
On Thu, 02 Mar 2006 11:41:12 +0800, dottty wrote:
Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql query?
I find this surprisingly difficult, given the fact that i can sum the
total
pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
Blimey, is that sql? Given the standard rider about this *not* being a
mysql support group, something like the (untested) suggestion below might
help:
select dept, count(*), sum(pay) from ... group by dept, order by dept;
Steve
No, it is not correct. Many use Postgres SQL, SQL Server, other
databases or no database at all.
You should ask MySQL question in a MySQL newsgroup - such as
comp.databases. mysql. *Everyone* there uses MySQL.
--
=============== ===
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp. js*******@attgl obal.net
=============== ===
"no.mail.pl s" <no*****@st.pet ers> wrote in message
news:44******** *************** @news.sunsite.d k... Hi,
Thanks for the prompt reply. However, i think it should be GROUP BY dept.
cheers
"Bosconian" <bo*******@plan etx.com> wrote in message
news:_p******** *************** *******@comcast .com... "dottty" <do****@noemail pls.met> wrote in message
news:44******** *************** @news.sunsite.d k... Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql
query?
I find this surprisingly difficult, given the fact that i can sum the
total pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
SELECT Count(dept) AS deptcount
FROM [table]
GROUP BY id
You're right and I know better. Serves me right for responding hastily just
as the pizza's being delivered. :-]
"no.mail.pl s" <no*****@st.pet ers> wrote in message
news:44******** *************** @news.sunsite.d k... Hi Steve,
Thanks for the reply. It works.
i am aware that this is not a sql group, but i beg your indulgence, as i
am quite sure that you guys will respond,
because i believe that most folks who use PHP
will also be using mysql.
is that correct?
cheers
"Steve" <Th*****@Aint.V alid> wrote in message
news:pa******** *************** *****@Aint.Vali d... On Thu, 02 Mar 2006 11:41:12 +0800, dottty wrote:
Hi,
i have a table that has the following fields:
id, name, dept, pay
1, John, Sales, 4000
2, Peter, HR, 5000
etc.
How do i count how many people there are in each dept with an sql
query?
I find this surprisingly difficult, given the fact that i can sum the
total
pay for each dept by using:
$query="
Select sum(if (dept='HR', pay, 0)) as hrpay, ......
";
TIA
Blimey, is that sql? Given the standard rider about this *not* being a
mysql support group, something like the (untested) suggestion below
might help:
select dept, count(*), sum(pay) from ... group by dept, order by dept;
Steve
I'm with you. PHP and MySQL are virtually joined at the hip. Look no further
than www.opensourcecms.com for proof. bo*******@plane tx.com says... because i believe that most folks who use PHP
will also be using mysql.
I'm with you. PHP and MySQL are virtually joined at the hip. Look no further
than www.opensourcecms.com for proof.
And yet here I sit churning away on PHP/AdoDB/Oracle ...
comp.databases. mysql is far better for straight MySQL advice.
Geoff M
Hiya,
Thanks for all the responses. i have never used mysql usenet groups, so i
just popped in to take a look, and found that they are at least an order
less popular than the php groups. On my ISP, i found the following number of
posts for these groups:
comp.lang.php - 22296 posts
comp.databases. mysql - 1067 posts
alt.comp.databa ses.mysql - 128 posts
i know it is a poor excuse for posting here though, but it is kind of you
folks to reply.
The huge difference in the number of posts sets me wondering... is it much
easier to use SQL than PHP, and so there is nothing much to discuss? Or are
there some other reasons?
cheers
"Geoff Muldoon" <ge***********@ trap.gmail.com> wrote in message
news:MP******** *************** *@news.readfree news.net... bo*******@plane tx.com says...
> because i believe that most folks who use PHP
> will also be using mysql.
I'm with you. PHP and MySQL are virtually joined at the hip. Look no
further
than www.opensourcecms.com for proof.
And yet here I sit churning away on PHP/AdoDB/Oracle ...
comp.databases. mysql is far better for straight MySQL advice.
Geoff M This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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