in_array() wierdness with arrays inside of $_POST

[AJ Z]

I am using in_array() to search for a value ("other"), in order to validate
a form.
If I pass $_POST["interests"] as the array to search PHP says that it is an
invalid datatype.
It is an array and if I copy it to another variable (i.e. $list =
$_POST["interests"];) it works fine.
The same is also true of implode().

Do you believe this is intended or is it a bug?
--
AJ Zmudosky
There are no stupid questions, but there are a LOT of inquisitive idiots.

[Rahul Anand]

AJ Z <us****@gwws.ne t> wrote in message news:<200402021 9572116807%usen et@gwwsnet>...

On 2004-02-01 22:25:57 -0800, ra************@ rediffmail.com (Rahul Anand)
said:
..

post a sample code if it still not solved.

--
Cheers,
Rahul Anand

Even with your suggestion on trim() I get the warning. Confirmed in_array()
args are in the correct order.

It works at my system [PHP 5]

[SNIP]

$_POST['key'] = array('aKey'=>' aValue','bKey'= >'bValue');

// Remove excess spaces
foreach ($_POST as $key => $val)
if(!is_array($v al))
$_POST[$key] = trim($val);

print_r($_POST) ;
exit;

[/SNIP]

Run this code to check it working. If it works, then receive the array
from a form post. I assure you that, it will execute smoothly.

You might have coded wrong, so please post the code you are trying to
execute.

--
Cheers,
Rahul Anand

[AJ Z]

On 2004-02-03 00:59:23 -0800, ra************@ rediffmail.com (Rahul Anand)
said:
...

Your code does execute without errors, and shows up.
I also ran it through in_array (searching for 'aValue') and it generated no
warnings.
However, my array also returns true for is_array(), but gives the warning.
The entire source code for the form can be seen at:
http://www.gwws.net/form.phps
If you would like it posted here I can trim it down and post it.
--
AJ Zmudosky
There are no stupid questions, but there are a LOT of inquisitive idiots.

[Rahul Anand]

AJ Z <us****@gwws.ne t> wrote in message news:<200402030 7093975249%usen et@gwwsnet>...

On 2004-02-03 00:59:23 -0800, ra************@ rediffmail.com (Rahul Anand)
said:
..

Your code does execute without errors, and shows up.
I also ran it through in_array (searching for 'aValue') and it generated no
warnings.
However, my array also returns true for is_array(), but gives the warning.
The entire source code for the form can be seen at:
http://www.gwws.net/form.phps
If you would like it posted here I can trim it down and post it.

I checked the code and found the reason for the error you are getting.
Here goes the explanation:

Line 10:
[SNIP]

if (is_array($_POS T["interests"])) { echo "'interests ' IS AN ARRAY<br
/>\n"; } else { echo "'interests ' IS AN ARRAY<br />\n"; }

[/SNIP]

In both case you are printing "'interests ' IS AN ARRAY".
Change the else part, and you will notice *interests* is not array in
all cases.

Reason:
PHP forms an array only when there is atleast one checkbox checked.
Because a form only sends the checked checkbox values.

Solution:
Before trying to operate on intersts array you need to test the array
with *isempty* or *isset* or *isarray*

Hope it will help.

--
Rahul Anand