preg_match_all ? quantifier problem

[Han]

The following pattern (which is one subpattern in a string of several) looks
for the following

$xxx,xxx.xx (with the dollar sign)

or

xxx,xxx.xx (space in replace of missing dollar sign)

It works great WITHOUT a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))

but fails WITH a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))?

I need the rest of the pattern results, not matter if this subpattern exists
or not. If it doesn't exist, I need the respective array value to be empty.

What's wrong with my syntax?

Thanks.

[Thomas Mlynarczyk]

Also sprach Han:

The following pattern (which is one subpattern in a string of
several) looks for the following

$xxx,xxx.xx (with the dollar sign)

or

xxx,xxx.xx (space in replace of missing dollar sign)

It works great WITHOUT a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))

but fails WITH a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))?
It does not fail, but it gives unexpected results. This regex translates
into "match the above pattern OR match an empty string".
I need the rest of the pattern results, not matter if this subpattern
exists or not.
preg_match_all will give you all the matches it finds. Just have a look at
the array of found matches (print_r()).
If it doesn't exist, I need the respective array value
to be empty.

$test = '$123,123.12</b> $1,1.1</b> $23,23.23</b>';
$pattern = '/(?:\\$|\s*)(?:\ d{1,3}\,)?\d{1, 3}\.\d{2}(?:</b>)/';
preg_match_all( $pattern, $test, $result);
echo '<pre>'; print_r($result ); echo '</pre>';

Note that I stripped the additional parentheses around the whole regex.
Now, $result should be:

$result[0] = '$123,123.12</b>'
$result[1] = '$23,23.23</b>'
(as '$1,1.1</b>' does not match)

Do I understand you right, that, in the above case, you would like $result
to be

$result[0] = '$123,123.12</b>'
$result[1] = ''
$result[2] = '$23,23.23</b>'

Well, that would be a bit more difficult (Remember, that anything could be
there instead of the "almost correct" $1,1.1</b>). You'd have to extend your
regex to something like "Match the valid pattern as before and capture them
with parentheses nr. 1 (that's your original regex) OR match any invalid
pattern, but don't capture them." Then use preg_match_all with the flag
PREG_SET_ORDER and in the result array, check for every index if
second-level index 1 exists. If so, it should contain your valid subpattern,
if not, then you have an invalid pattern at second-level index 0.

Greetings, Thomas

[Han]

Thom,

Thanks for your reply.

It seems like trying to include this and other conditional requirements in
one pass might be asking for too much. It will ultimately be much easier to
simply capture larger blocks of markup and parse them accordingly upon
outputting to the page.

Your explanation was very instructive though and I sincerely appreciate your
time.

"Thomas Mlynarczyk" <bl************ *@hotmail.com> wrote in message
news:bm******** *****@news.t-online.com...

Also sprach Han:

The following pattern (which is one subpattern in a string of
several) looks for the following

$xxx,xxx.xx (with the dollar sign)

or

xxx,xxx.xx (space in replace of missing dollar sign)

It works great WITHOUT a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))

but fails WITH a ? quantifier

((?:\\$|\s*)(?: \d{1,3}\,)?\d{1 ,3}\.\d{2}(?:</b>))?
It does not fail, but it gives unexpected results. This regex translates
into "match the above pattern OR match an empty string".

I need the rest of the pattern results, not matter if this subpattern
exists or not.

preg_match_all will give you all the matches it finds. Just have a look at
the array of found matches (print_r()).

If it doesn't exist, I need the respective array value
to be empty.

$test = '$123,123.12</b> $1,1.1</b> $23,23.23</b>';
$pattern = '/(?:\\$|\s*)(?:\ d{1,3}\,)?\d{1, 3}\.\d{2}(?:</b>)/';
preg_match_all( $pattern, $test, $result);
echo '<pre>'; print_r($result ); echo '</pre>';

Note that I stripped the additional parentheses around the whole regex.
Now, $result should be:

$result[0] = '$123,123.12</b>'
$result[1] = '$23,23.23</b>'
(as '$1,1.1</b>' does not match)

Do I understand you right, that, in the above case, you would like $result
to be

$result[0] = '$123,123.12</b>'
$result[1] = ''
$result[2] = '$23,23.23</b>'

Well, that would be a bit more difficult (Remember, that anything could be
there instead of the "almost correct" $1,1.1</b>). You'd have to extend

your regex to something like "Match the valid pattern as before and capture them with parentheses nr. 1 (that's your original regex) OR match any invalid
pattern, but don't capture them." Then use preg_match_all with the flag
PREG_SET_ORDER and in the result array, check for every index if
second-level index 1 exists. If so, it should contain your valid subpattern, if not, then you have an invalid pattern at second-level index 0.

Greetings, Thomas