Hello,
I need help for php syntax when i call Mysql database
I have wrote that and my sql connection is working
I just have a problem with this command line :
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
Thanks to help me and to give me correct syntax
Julien from France
7  3817 
"Julien - Marseille" <be************ @hotmail.com> schreef in bericht
news:bk******** **@s1.read.news .oleane.net... Hello,
I need help for php syntax when i call Mysql database
I have wrote that and my sql connection is working
I just have a problem with this command line :
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
Thanks to help me and to give me correct syntax
Julien from France
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
should be:
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login'";
(delete the semicolon after ...'$login'.... .)
A la tienne!
Marcel
Julien - Marseille wrote: Hello,
I need help for php syntax when i call Mysql database
I have wrote that and my sql connection is working
I just have a problem with this command line :
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
Thanks to help me and to give me correct syntax
Julien from France
hi,
i think your $login variable is not evaluated because it's enclosed by
simple quotes that override the variable evaluation mechanism.
you've got to write :
"SELECT * FROM utilisateurs WHERE pseudo_utilisat eur='".$login." ';"
cheers.
On Wed, 24 Sep 2003 16:54:06 +0200, cédric wrote: $query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
Thanks to help me and to give me correct syntax
Julien from France
hi,
i think your $login variable is not evaluated because it's enclosed by
simple quotes that override the variable evaluation mechanism. you've got
to write :
"SELECT * FROM utilisateurs WHERE pseudo_utilisat eur='".$login." ';"
cheers.
Nope.. the $var is perfectly fine within single quotes like that, because
the _actual_ string is enclosed in double-quotes (" ").. the singles are
quoted as _part_ of the string, not as a string definition. However:
$query = "
SELECT *
FROM utilisateurs
WHERE pseudo_utilisat eur = '$login'
";
$acces = mysql_query($qu ery);
should work.
Notice the semi-colon has been dropped after '$login'. I suspect (without
seeing any other posts in this thread) that this is causing a problem.
Regards,
Ian
--
Ian.H [Design & Development]
digiServ Network - Web solutions www.digiserv.net | irc.digiserv.ne t | forum.digiserv. net
Programming, Web design, development & hosting.
On 24-Sep-2003, "Julien - Marseille" <be************ @hotmail.com> wrote: I need help for php syntax when i call Mysql database
I have wrote that and my sql connection is working
I just have a problem with this command line :
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
The code you have shown us is correct, assuming that the table name and
column name are correct, the db is open, mysql is installed, etc.
What syntax error are you getting? If you add 'or die(mysql_error ())' after
the mysql_query(), you will get an error message if you have a mysql syntax
error.
Contrary to other posts, the semicolon in the SQL string is not needed, but
not an error and the 's around the $login are correct, too.
--
Tom Thackrey www.creative-light.com
"Julien - Marseille" <be************ @hotmail.com> wrote in message news:<bk******* ***@s1.read.new s.oleane.net>.. . Hello,
I need help for php syntax when i call Mysql database
I have wrote that and my sql connection is working
I just have a problem with this command line :
$query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
$acces = mysql_query($qu ery);
PS : Login = Julien
Thanks to help me and to give me correct syntax
Julien from France
Je ne sais pas si le problème est réglé mais as-tu essayé de mettre 2 signes "=" ?
....where '$var1' == '$var2'...
benoit
québec
On 24 Sep 2003 17:26:33 -0700, Ben wrote: "Julien - Marseille" <be************ @hotmail.com> wrote in message news:<bk******* ***@s1.read.new s.oleane.net>.. . $query = "SELECT * FROM utilisateurs WHERE
pseudo_utilisat eur='$login';";
You can't have the ";" sent to MySQL.
Remove it from $query and you should be ok.
Anyway ... it always pays to know why something does not work in MySQL:
<?php
$result = mysql_query($qu ery) or die(mysql_error ());
?>
Prints the MySQL error message if there was one in $query.
Je ne sais pas si le problème est réglé mais as-tu essayé de mettre 2 signes "=" ?
...where '$var1' == '$var2'...
(mon francais c'est tres mauvais)
ca ne va pas! En MySQL le test de equalite ce fait avec un seule "=".
Deux signes "=" fonctionne bien en PHP, pas en MySQL.
Mais ... bonne idee :)
--
I have a spam filter working.
To mail me include "urkxvq" (with or without the quotes)
in the subject line, or your mail will be ruthlessly discarded.
I noticed that Message-ID: <bk************ @ID-203069.news.uni-berlin.de>
from Pedro contained the following: (mon francais c'est tres mauvais)
Mon francais est plus mal. ;-)
ca ne va pas! En MySQL le test de equalite ce fait avec un seule "=".
Deux signes "=" fonctionne bien en PHP, pas en MySQL.
Mais je comprend qu'est-ceque c'est que vous dit. :)
--
Geoff Berrow
It's only Usenet, no one dies.
My opinions, not the committee's, mine.
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