I am a Perl Programmer & i am using WIN32::OLE for Excel operations.
I wanted to use conditional formulas like 'if' in excel via Perl.
Thanks in Advance.
13 4689 miller 1,089
Recognized Expert Top Contributor
I personally would use Spreadsheet::Wr iteExcel as Win32::OLE does not provide great documentation.
At the very least, maybe you could create a test excel file with functions and examine it using Win32::OLE to determine how they are included.
- Miller
Hi Miller,
Thanks for your Interest & I found the answer. -
"=IF(RC[$prev]>RC[$curr],RC[$prev]-RC[$curr],\"PASS\")"
-
The reason why i am using Win32::OLE is, no need of additional Module Installation.
miller 1,089
Recognized Expert Top Contributor
Of course, Just note that anytime you want to use quotes " instead of an interpolated string, you can use the qq operator instead. -
qq{=IF(RC[$prev]>RC[$curr],RC[$prev]-RC[$curr],"PASS")}
-
Thanks Miller.
But Folks, any idea on Arithmetic Operation with Strings?
Ex : I can do auto increment of string : my $a = 'A';
$a ++ ; #Will give 'B'
Like that, i want to do : $a += 5 ; #I expect 'F', but perl throws error on this. Any idea on my thing?
RonB 589
Recognized Expert Moderator Contributor
When you do $a++, perl will increment the ascii value, but when you do $a += 5, you're attempting to add a numerical number which is not the same.
To accomplish what you want, you'd need to do this. - my $letter = 'a';
-
$letter = chr(ord($letter)+5);
miller 1,089
Recognized Expert Top Contributor
As RonB pointed out, the fact that the increment ++ and decrement -- operators work on strings is a special feature. To get the same behavior out of += or any other operator would require overloading them.
The best method is to just use the method that RonB demonstrated.
- Miller
Thanks Guys for your Awesome Response!!!
RonB,
I accept that. But even with this option i have a problem:
my $letter = 'A';
my $test;
for ($i = 1; $i <= 100; $i++){
$test = chr(ord($letter ));
print "Orig Char : $letter; Exp Char : $test\n";
$letter++;
}
This will fine upto 26 (A to Z), After 26th Iteration, $letter will become 'AA' where the function will fail (Since it will take 1 char as argument).
Any alternative way to address this problem.
miller 1,089
Recognized Expert Top Contributor
Yes, if you increment a string it will go from A to Z and then to AA AB, etc. You say that's not what you want, but you haven't described what your ideal behavior actually is?
What are you wanting your string incrementor to do? In theory you're going through 100 values, what do you want them to be?
Miller,
At the begining i mentioned that i am working in Excel.
The Excel Cells Starts from 'A' & it goes like AA - AZ, BA - BZ & so on.. This is my Use case!
Hope it will narrow your ideas.
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