Hi all,
Im trying to execute this statement in SQL Plus but am getting the
error not a single-group group function. My code is below. To explain
what Im trying to get at, I want to return the total grade for g.grade
that has been multiplied by its appropriate weight that it carries
towards the total grade.
SELECT g.section_id, g.student_id, g.grade_type_co de,
SUM((AVG(g.grad e)*30/100+AVG(g.grade )
*20/100+AVG(g.grade )*20/100+AVG(g.grade )*10/100+AVG(g.grade )*20/100))
FROM grade g, grade_type_weig ht gtw
WHERE g.student_id = 270
AND g.section_id = gtw.section_id
AND g.grade_type_co de = gtw.grade_type_ code
GROUP BY g.section_id, g.student_id,
g.grade_type_co de
Any help is greatly appreciated:>
Moon
3  15767 
You will have to group by g.grade_type_co de as well GROUP BY g.section_id, g.student_id, g.grade_type_co de
M
em***@yahoo.com (moon) wrote in message news:<f4******* *************** ****@posting.go ogle.com>... Hi all,
Im trying to execute this statement in SQL Plus but am getting the
error not a single-group group function. My code is below. To explain
what Im trying to get at, I want to return the total grade for g.grade
that has been multiplied by its appropriate weight that it carries
towards the total grade.
SELECT g.section_id, g.student_id, g.grade_type_co de,
SUM((AVG(g.grad e)*30/100+AVG(g.grade )
*20/100+AVG(g.grade )*20/100+AVG(g.grade )*10/100+AVG(g.grade )*20/100))
FROM grade g, grade_type_weig ht gtw
WHERE g.student_id = 270
AND g.section_id = gtw.section_id
AND g.grade_type_co de = gtw.grade_type_ code
GROUP BY g.section_id, g.student_id,
g.grade_type_co de
Any help is greatly appreciated:>
Moon em***@yahoo.com (moon) wrote in message news:<f4******* *************** ****@posting.go ogle.com>... Hi all,
Im trying to execute this statement in SQL Plus but am getting the
error not a single-group group function. My code is below. To explain
what Im trying to get at, I want to return the total grade for g.grade
that has been multiplied by its appropriate weight that it carries
towards the total grade.
SELECT g.section_id, g.student_id, g.grade_type_co de,
SUM((AVG(g.grad e)*30/100+AVG(g.grade )
*20/100+AVG(g.grade )*20/100+AVG(g.grade )*10/100+AVG(g.grade )*20/100))
FROM grade g, grade_type_weig ht gtw
WHERE g.student_id = 270
AND g.section_id = gtw.section_id
AND g.grade_type_co de = gtw.grade_type_ code
GROUP BY g.section_id, g.student_id,
g.grade_type_co de
Any help is greatly appreciated:>
Moon
The error is due to the nesting of the functions, I believe. IOW,
SUM((AVG(... is not allowed.
Try creating an inline view.
Why the extra set of parentheses?
AND, WHY are you computing it this way?
SUM((AVG(g.grad e)*30/100
+AVG(g.grade)*2 0/100
+AVG(g.grade)*2 0/100
+AVG(g.grade)*1 0/100
+AVG(g.grade)*2 0/100))
Isn't that the same as SUM(AVG(g.grade )) ????
(I don't think my math is that rusty, or is it??)
Ed
Hi,
Try this
SElECT a.section_id , a.student_id , a.grade_type_co de , SUM(a.averageco l) FROM
( SELECT g.section_id, g.student_id, g.grade_type_co de,
(AVG(g.grade)*3 0/100+AVG(g.grade )
*20/100+AVG(g.grade )*20/100+AVG(g.grade )*10/100+AVG(g.grade )*20/100) avaragecol
FROM grade g, grade_type_weig ht gtw
WHERE g.student_id = 270
AND g.section_id = gtw.section_id
AND g.grade_type_co de = gtw.grade_type_ code
GROUP BY g.section_id, g.student_id,
g.grade_type_co de ) a
Group by a.section_id , a.student_id , a.grade_type_co de em*****@yahoo.c o.uk (SoulSurvivor) wrote in message news:<1c******* *************** ****@posting.go ogle.com>... You will have to group by g.grade_type_co de as well
GROUP BY g.section_id, g.student_id, g.grade_type_co de
M
em***@yahoo.com (moon) wrote in message news:<f4******* *************** ****@posting.go ogle.com>... Hi all,
Im trying to execute this statement in SQL Plus but am getting the
error not a single-group group function. My code is below. To explain
what Im trying to get at, I want to return the total grade for g.grade
that has been multiplied by its appropriate weight that it carries
towards the total grade.
SELECT g.section_id, g.student_id, g.grade_type_co de,
SUM((AVG(g.grad e)*30/100+AVG(g.grade )
*20/100+AVG(g.grade )*20/100+AVG(g.grade )*10/100+AVG(g.grade )*20/100))
FROM grade g, grade_type_weig ht gtw
WHERE g.student_id = 270
AND g.section_id = gtw.section_id
AND g.grade_type_co de = gtw.grade_type_ code
GROUP BY g.section_id, g.student_id,
g.grade_type_co de
Any help is greatly appreciated:>
Moon This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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