How to get the file and path information.

[Hengiccs]

Hello,
I'm a beginner for vb.net. Now i have to create a ftp function that allow me to right click on a file and click on the option on the right click menu to ftp the file to a server. Can anyone teach me how to get the file and path information when right on the file like winzip or winrar. Then i also facing a problem for allow me to ftp a folder and the content inside the folder to a server by using vb.net 2005 FtpWebRequest.

[channaJ]

Hello,
I'm a beginner for vb.net. Now i have to create a ftp function that allow me to right click on a file and click on the option on the right click menu to ftp the file to a server. Can anyone teach me how to get the file and path information when right on the file like winzip or winrar. Then i also facing a problem for allow me to ftp a folder and the content inside the folder to a server by using vb.net 2005 FtpWebRequest.

Hi Hengiccs,

Sorry but I can't understand the first part of your problem. From where are you gonna access the file path?

In the second case, you cannot FTP a folder. You have to send the files seperately to the server. The following code will help you on this.

string CompleteFTPPath = "ftp://channaj/test.txt";
string CompleteLocalPath = "D:\MyTests\test.txt";
 FtpWebRequest FtpRequest = (FtpWebRequest)WebRequest.Create(CompleteFTPPath);
            FtpRequest.Method = WebRequestMethods.Ftp.UploadFile;
            FtpRequest.Proxy = null;
 
            Stream requestStream = FtpRequest.GetRequestStream();
            FileStream fileStream = File.OpenRead(CompleteLocalPath);
            byte[] buffer = new byte[fileStream.Length];
            fileStream.Read(buffer, 0, buffer.Length);
            fileStream.Close();
            requestStream.Write(buffer, 0, buffer.Length);
            requestStream.Close(); 

In this code CompleteFTPPath is the complete path of the file in the FTP server. CompleteLocalPath is the complete path of the file in the local machine.

If you want to send a list of files, you have to call this code inside a loop. You cannot FTP a folder.

[Hengiccs]

Hi Hengiccs,

Sorry but I can't understand the first part of your problem. From where are you gonna access the file path?

In the second case, you cannot FTP a folder. You have to send the files seperately to the server. The following code will help you on this.

string CompleteFTPPath = "ftp://channaj/test.txt";
string CompleteLocalPath = "D:\MyTests\test.txt";
 FtpWebRequest FtpRequest = (FtpWebRequest)WebRequest.Create(CompleteFTPPath);
            FtpRequest.Method = WebRequestMethods.Ftp.UploadFile;
            FtpRequest.Proxy = null;
 
            Stream requestStream = FtpRequest.GetRequestStream();
            FileStream fileStream = File.OpenRead(CompleteLocalPath);
            byte[] buffer = new byte[fileStream.Length];
            fileStream.Read(buffer, 0, buffer.Length);
            fileStream.Close();
            requestStream.Write(buffer, 0, buffer.Length);
            requestStream.Close(); 

In this code CompleteFTPPath is the complete path of the file in the FTP server. CompleteLocalPath is the complete path of the file in the local machine.

If you want to send a list of files, you have to call this code inside a loop. You cannot FTP a folder.

===================

Dear channaJ ,
Really thanks for your help, actually the first part of my problem is, i have to add an option click on my right click menu after i had installed my deployed program. It's just look like those winzip program, so now what i want to do is, when i right click on a file (file highlighted) or a folder then the right click menu will pop out. In order that i can send the file to a server, i will click on the option on the right click menu then a form with some information and a send button will pop out. When i click on send button the file will be ftp to the server. Inside my code i have to know where the files located at,(path information) then i just can get the file information and send it out. So, i have to get the file information when i right click on it, then pass the information to my program. Really sorry for i don't know how to explain on it, because my english not good enough. Thanks again for your kindness.

[channaJ]

===================

Dear channaJ ,
Really thanks for your help, actually the first part of my problem is, i have to add an option click on my right click menu after i had installed my deployed program. It's just look like those winzip program, so now what i want to do is, when i right click on a file (file highlighted) or a folder then the right click menu will pop out. In order that i can send the file to a server, i will click on the option on the right click menu then a form with some information and a send button will pop out. When i click on send button the file will be ftp to the server. Inside my code i have to know where the files located at,(path information) then i just can get the file information and send it out. So, i have to get the file information when i right click on it, then pass the information to my program. Really sorry for i don't know how to explain on it, because my english not good enough. Thanks again for your kindness.

Ah...you are gonna play with the registry then. OK.

Hope you have created the particular registry keys. What you have to do here is passing the file path from the registry, when you are invoking your application. You can access this value from the main method of your app.

Add String[] args as a parameter of your main method. the file path will come as an element in args array.

You can pass the file path by adding "%L" element at the end of the path of the exe in the registry.

Hope this will make sence.:) Let me know if not.

[Hengiccs]

Ah...you are gonna play with the registry then. OK.

Hope you have created the particular registry keys. What you have to do here is passing the file path from the registry, when you are invoking your application. You can access this value from the main method of your app.

Add String[] args as a parameter of your main method. the file path will come as an element in args array.

You can pass the file path by adding "%L" element at the end of the path of the exe in the registry.

Hope this will make sence.:) Let me know if not.

================================================

Dear channaJ,
Ohh, thanks for reply me again. But really sorry for i not really understand how to do it? is it i have to add %L in the registry key value like ( C:\Program Files\TechStudioUV\Transfer files\Ftpfile.exe%L ). if yes, in the main method how to i get the file information? is it when i start run my program in the part of form1_load? Again, thank you very much.

[channaJ]

================================================

Dear channaJ,
Ohh, thanks for reply me again. But really sorry for i not really understand how to do it? is it i have to add %L in the registry key value like ( C:\Program Files\TechStudioUV\Transfer files\Ftpfile.exe%L ). if yes, in the main method how to i get the file information? is it when i start run my program in the part of form1_load? Again, thank you very much.

This is how you should add it to your registry key.

C:\Program Files\TechStudioUV\Transfer files\Ftpfile.exe "%L"

Once you do this, the path of the file on which you right clicked, is passed as a parameter to the Main() method of your programe. By default your Main() method does not take any parameter. So edit your Main() method as follows.

static void Main(String [] args)
{
   string filePath = args[0];
}

Clear now ? Let me know if not.

Regards
Channa

[Hengiccs]

This is how you should add it to your registry key.

C:\Program Files\TechStudioUV\Transfer files\Ftpfile.exe "%L"

Once you do this, the path of the file on which you right clicked, is passed as a parameter to the Main() method of your programe. By default your Main() method does not take any parameter. So edit your Main() method as follows.

static void Main(String [] args)
{
   string filePath = args[0];
}

Clear now ? Let me know if not.

Regards
Channa

===================

Dear channaJ,
Thanks channaJ. But it seem like i still have problem here. The VB.net 2005 don't have the startup object with Sub Main(). Only if, when i uncheck the checkbox of Enable application framework in the my project and put my sub main() to a new module it just will run the sub main(). When i try to right click on a file to pass the path information to my program, it pop up a error messagebox with path information and a warning "Access is denied". Then i not sue whether the sub main() for vb.net that i code is correct or not. e.g:

Public Sub Main(ByVal agrs1() As String)
Dim filepath As String = agrs1(0)
MsgBox(filepath.ToString)
End Sub

Best Regard
Hengiccs

[channaJ]

===================

Dear channaJ,
Thanks channaJ. But it seem like i still have problem here. The VB.net 2005 don't have the startup object with Sub Main(). Only if, when i uncheck the checkbox of Enable application framework in the my project and put my sub main() to a new module it just will run the sub main(). When i try to right click on a file to pass the path information to my program, it pop up a error messagebox with path information and a warning "Access is denied". Then i not sue whether the sub main() for vb.net that i code is correct or not. e.g:

Public Sub Main(ByVal agrs1() As String)
Dim filepath As String = agrs1(0)
MsgBox(filepath.ToString)
End Sub

Best Regard
Hengiccs

Hi Hengiccs,

Since VB.net doesn't give you a Sub Main() by default, what you have done is correct. As far as I understand the problem you are having now is something else. Check the permisions you have for the particular folder. Check permissions you have for the registry. Check whether your registry key is in order by calling a different exe. Do some experiments. ( I myself tried this with VB.net after your last reply. This worked just fine in my machine.) I think you are almost there. All the best.

Regards
Channa

[Hengiccs]

Hi Hengiccs,

Since VB.net doesn't give you a Sub Main() by default, what you have done is correct. As far as I understand the problem you are having now is something else. Check the permisions you have for the particular folder. Check permissions you have for the registry. Check whether your registry key is in order by calling a different exe. Do some experiments. ( I myself tried this with VB.net after your last reply. This worked just fine in my machine.) I think you are almost there. All the best.

Regards
Channa

=======================
Dear Channaj

ohh..., i will try to check for it now. i really feel appreciate for your help. Thanks a lot. :D

Best regard
Hengiccs