xsl problem using charriage return

[judy]

I have an xml file containing a series of names, first name and last
name. My desired outcome is to create an xsl file that will generate a
comma delimitated text file containing these names. I need first name/
comma/ last name /carriage return. The first name comma last name work
fine. Can't get the carriage return.

Any suggestions would be helpful.

<?xml version="1.0"?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">

<xsl:for-each select="list/name">

<xsl:value-of select="fname"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="lname"/>
<xsl:text>,</xsl:text>
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>

My problem is the &#13 carriage return. I think this should work, but
no such luck.

I'm using Instant Saxon to parse the document.

[Wole Ogunremi]

try &#xd; for character 13, and &#xa; for character 10

<judy> wrote in message news:bb******** *************** *********@4ax.c om...

I have an xml file containing a series of names, first name and last
name. My desired outcome is to create an xsl file that will generate a
comma delimitated text file containing these names. I need first name/
comma/ last name /carriage return. The first name comma last name work
fine. Can't get the carriage return.

Any suggestions would be helpful.

<?xml version="1.0"?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">

<xsl:for-each select="list/name">

<xsl:value-of select="fname"/>
<xsl:text>,</xsl:text>
<xsl:value-of select="lname"/>
<xsl:text>,</xsl:text>
<xsl:text> </xsl:text>
</xsl:for-each>
</xsl:template>

</xsl:stylesheet>

My problem is the &#13 carriage return. I think this should work, but
no such luck.

I'm using Instant Saxon to parse the document.

[Patrick TJ McPhee]

[I haven't seen the original question]

% <judy> wrote in message news:bb******** *************** *********@4ax.c om...

% > fine. Can't get the carriage return.
% >
% > Any suggestions would be helpful.
% >
% > <?xml version="1.0"?>
% > <xsl:styleshe et version="1.0"
% > xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">

The problem is right here. You don't specify an output format, so your
xslt processor assumes you want the default format, xml. It ends up
looking like text because you don't add any elements to the result
tree, but looks can be deceiving. If you add

<xsl:output method='text'/>

at this point in the style sheet, you should get the result you want.

--

Patrick TJ McPhee
North York Canada
pt**@interlog.c om