Use Parameter value in match or select - 'Parameterized XPath expressions ?'

[Colin Toal]

Hi all,

I'm starting to learn XSLT - and have what I think is a very basic
question:

I have a stylesheet like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="objectnam e"/>

<xsl:template match="/Root">
<xsl:apply-templates select="./$objectname"/>
</xsl:template>

<xsl:template match="$objectn ame">
<Result>
<xsl:value-of select="."/>
</Result>
</xsl:template>

</xsl:stylesheet>

and XML like this:

<?xml version="1.0" ?>
<Root>
<Value1>1</Value1>
<Value2>2</Value2>
<Value3>3</Value3>
</Root>

Now, I'd like to pass a name of a child element of Root (like Value1
or Value2) from a Java class into this stylesheet as param
'objectname'.

I can pass the parameter fine (I have tested this), but I understand
that this won't work because the XSLT interpretor cannot resolve the
value of $objectname as part of an XPath expression representing a
nodeset.

What I'd like to know is if there is some way to accomplish the same
thing ? I apologize if this question has been asked a million times by
a million newbies in the past, but I haven't found a way to do it yet
- I've even considered resorting to something 'strange' like running
my XSLT template through another XSLT template that resolves all the
'parameterized XPath expressions' into their explicit forms - but that
feels 'terribly inelegant'.

Thanks in advance - please reply directly as above.
Colin

[DFN-CIS NetNews Service]

On 22/01/2004, around 15:14, Colin Toal wrote:

CT> What I'd like to know is if there is some way to accomplish the same
CT> thing ?

Try

<xsl:template match="/Root">
<xsl:apply-templates select="./*[name() = $objectname]"/>
</xsl:template>

--
Stuart
The darkest hour is just before dawn. So if you're going to steal your
neighbour's milk, that's the time to do it.

[Martin Honnen]

Colin Toal wrote:

I have a stylesheet like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="objectnam e"/>

<xsl:template match="/Root">
<xsl:apply-templates select="./$objectname"/>
</xsl:template>

<xsl:template match="$objectn ame">
<Result>
<xsl:value-of select="."/>
</Result>
</xsl:template>

</xsl:stylesheet>

and XML like this:

<?xml version="1.0" ?>
<Root>
<Value1>1</Value1>
<Value2>2</Value2>
<Value3>3</Value3>
</Root>

Now, I'd like to pass a name of a child element of Root (like Value1
or Value2) from a Java class into this stylesheet as param
'objectname'.

I can pass the parameter fine (I have tested this), but I understand
that this won't work because the XSLT interpretor cannot resolve the
value of $objectname as part of an XPath expression representing a
nodeset.

XPath has a function local-name() so you could have an XPath alike
*[local-name() = $objectname]
to select elements with the name passed in.
--

Martin Honnen
http://JavaScript.FAQTs.com/

[Colin Toal]

Martin Honnen <ma*******@yaho o.de> wrote in message news:<40******* *@olaf.komtel.n et>...

Colin Toal wrote:

I have a stylesheet like this:

<?xml version="1.0" encoding="UTF-8"?>
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0">
<xsl:param name="objectnam e"/>

<xsl:template match="/Root">
<xsl:apply-templates select="./$objectname"/>
</xsl:template>

<xsl:template match="$objectn ame">
<Result>
<xsl:value-of select="."/>
</Result>
</xsl:template>

</xsl:stylesheet>

and XML like this:

<?xml version="1.0" ?>
<Root>
<Value1>1</Value1>
<Value2>2</Value2>
<Value3>3</Value3>
</Root>

Now, I'd like to pass a name of a child element of Root (like Value1
or Value2) from a Java class into this stylesheet as param
'objectname'.

I can pass the parameter fine (I have tested this), but I understand
that this won't work because the XSLT interpretor cannot resolve the
value of $objectname as part of an XPath expression representing a
nodeset.

XPath has a function local-name() so you could have an XPath alike
*[local-name() = $objectname]
to select elements with the name passed in.

Thank you for the help -

Will that work for 'match' expressions also ?

Colin