Context

[Eliza Zadura]

The following question is about XPath and context, as I am not sure I'm
grasping the concept entirely and this is causing me some problems while
working on my XSL transformation.

I have checked the XPath specification and am somewhat familiar with the
different addressing mechanisms. What confuses me is the context when
using templates and various (nested) <xsl:for-each>, <xsl:if> and
<xsl:when> expressions.

For example, say I have a named template where test-param is the value
of a certain node.

<xsl:template name="test_temp ">
<xsl:param name="test_para m"/>
...
...
<xsl:for-each select="[some other node]">

<!--here, I assume the context is that of [some other node], and not the
node represented by test_param?-->

<xsl:if test="[yet another node]">

<!--What about the context here, is it that of [yet another node]?-->

</xsl:if>
</xsl:for-each>

<!--And here, am I back to the original context, the one defined by the
test_param?-->

</xsl:template>

And so on, and so forth...
To put it briefly: Does every expression that evaluates a set of nodes
change the context to that particular set, thus enabling me to use ./
while referring to attributes or other subnodes of that node?

-----------------
Eliza Zadura
Trainee-Developer

*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!

[Marrow]

Hi Eliza,

For example, say I have a named template where test-param is the value
of a certain node.

<xsl:template name="test_temp ">
<xsl:param name="test_para m"/>
^^^^^ the context here will be whatever the context node was at the point of
the <xsl:call-template>. Parameters have no effect on the context. ..
..
<xsl:for-each select="[some other node]">

<!--here, I assume the context is that of [some other node], and not the
node represented by test_param?-->
^^^^^ yes, the context node will be the [some other node]
<xsl:if test="[yet another node]">

<!--What about the context here, is it that of [yet another node]?-->

</xsl:if>
</xsl:for-each>

<!--And here, am I back to the original context, the one defined by the
test_param?-->
^^^^^ No, because the context was never the node(s) in the $test_param - the
context will revert to the context node at the point of the
<xsl:call-template>
</xsl:template>

Hope this helps
Marrow
http://www.marrowsoft.com - home of Xselerator (XSLT IDE and debugger)
http://www.topxml.com/Xselerator
"Eliza Zadura" <el**********@s ync.se> wrote in message
news:3f******** *************** @news.frii.net. .. The following question is about XPath and context, as I am not sure I'm
grasping the concept entirely and this is causing me some problems while
working on my XSL transformation.

I have checked the XPath specification and am somewhat familiar with the
different addressing mechanisms. What confuses me is the context when
using templates and various (nested) <xsl:for-each>, <xsl:if> and
<xsl:when> expressions.

For example, say I have a named template where test-param is the value
of a certain node.

<xsl:template name="test_temp ">
<xsl:param name="test_para m"/>
..
..
<xsl:for-each select="[some other node]">

<!--here, I assume the context is that of [some other node], and not the
node represented by test_param?-->

<xsl:if test="[yet another node]">

<!--What about the context here, is it that of [yet another node]?-->

</xsl:if>
</xsl:for-each>

<!--And here, am I back to the original context, the one defined by the
test_param?-->

</xsl:template>

And so on, and so forth...
To put it briefly: Does every expression that evaluates a set of nodes
change the context to that particular set, thus enabling me to use ./
while referring to attributes or other subnodes of that node?

-----------------
Eliza Zadura
Trainee-Developer

*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!

[Eliza Zadura]

Thank you for your reply. That is what I thought, but I wanted it
confirmed.

What about if I have nested for loops? Will the context of the inner
loop be that of the inner select?

I'm having to do quite horrible loops and conditions to accomplish what
I need, and find all this a bit confusing...

-----------------
Eliza Zadura
Trainee-Developer

*** Sent via Developersdex http://www.developersdex.com ***
Don't just participate in USENET...get rewarded for it!