Adding onmouseover event to GridView's LinkButton

[RobertTheProgrammer]

Hi,

On an ASP.NET GridView, I have several LinkButton objects. I want to add the "onmouseove r" event to the LinkButton so that I can perform a javascript task-- in particular, to rewrite the window.status message so it shows a more meaningful message than the layman-confusing javascript link message.

So how do I add this "onmouseove r" event to the LinkButton? I'm stumped.

Thanks.

Robert

[Frinavale]

Hi,

On an ASP.NET GridView, I have several LinkButton objects. I want to add the "onmouseove r" event to the LinkButton so that I can perform a javascript task-- in particular, to rewrite the window.status message so it shows a more meaningful message than the layman-confusing javascript link message.

So how do I add this "onmouseove r" event to the LinkButton? I'm stumped.

Thanks.

Robert

I can't remember if you are coding in C# or VB.NET.

One way to solve this would be to implement the ITemplate class to customize a Template to be used for your GridView. If you don't have the time to learn how to do this...

In your GridView's RowDataBound event you can set the LinkButton's onmouseover event.....

  Dim lbtnAs LinkButton
           'if the row is a data row, grab the link button and set it's properties
        If e.Row.RowType = DataControlRowType.DataRow Then
            'The CType() method casts the object retrieved by the FindControl to a LinkButton object
            lbtnAs = CType(e.Row.FindControl("theLinkButtonControlName"),LinkButton)
            'As long as a LinkButton was returned...set the JavaScript
            If Not lbtnAs Is Nothing Then
                lbtnAs .Attributes.Add("onmouseover", "javascript:myJavaScriptFunction()")
            End If
        End If
 

Don't forget that LinkButtons have ToolTips...you could just set the LinkButton's ToolTip property to display additional information about said LinkButton instead ...

  Dim lbtnAs LinkButton
       'if the row is a data row, grab the link button and set it's properties
        If e.Row.RowType = DataControlRowType.DataRow Then
            'The CType() method casts the object retrieved by the FindControl method into a LinkButton
            lbtnAs = CType(e.Row.FindControl("theLinkButtonControlName"),LinkButton)
            'As long as a LinkButton was returned...set the ToolTip
            If Not lbtnAs Is Nothing Then
                lbtn.ToolTip="Additional information that is displayed when moused over the link button"
            End If
        End If
 

Cheers!

-Frinny

[RobertTheProgrammer]

It's a thing of beauty!

The code behind is in C#, but that's okay as I was able to adapt your suggestions.

On the RowDataBound event, I have code like this:

LinkButton AddButton = (LinkButton)e.Row.FindControl("lnkAdd");
if (AddButton != null) AddButton.Attributes.Add("onmouseover", "window.status='Click to insert a new record'; return true;");
 

Works great. Thank you very much for taking the time to reply. It's very much appreciated.

Robert