Hi guys im trying to telnet to an IP address that is entered into a textbox from the click of a button but im having problems as it just gives me errors when i run it. Here is my code: - Private Sub btnTelnet_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnTelnet.Click
-
Dim telnet As Process = New Process
-
telnet.StartInfo.FileName = "telnet.exe"
-
telnet.StartInfo.Arguments = "o" + txthostname.text
-
telnet.StartInfo.WindowStyle = ProcessWindowStyle.Normal
-
telnet.StartInfo.CreateNoWindow = True
-
telnet.Start()
-
End Sub
-
without the "telnet.StartIn fo.Arguments = "o" + txthostname.tex t" command it just opens telnet but with the code it says "unexpected error continue or quit".
Any help would be great
Cheers
8  5929  Plater 7,872
Recognized Expert Expert
Well uh, what are you trying to do?
I don't see you capturing the input/output/error streams, but you tell it to NOT create a window.
Well uh, what are you trying to do?
I don't see you capturing the input/output/error streams, but you tell it to NOT create a window.
Hi mate, thanks for the reply.
What im trying to do is enter an ethernet ip address into a textbox then click the "telnet button" which opens up microsoft telent command prompt and automatically enters in the IP address that was entered in to the text box and telnets to the interface...thi s is so basically the user doesnt need to enter a IP address when telnet opens.
Does anyone know how to do this in code?
Thanks in advance
Plater 7,872
Recognized Expert Expert
Well if that is the case, be sure to remove this line:
telnet.StartInf o.CreateNoWindo w = True
so a window will popup for the user to see.
Well if that is the case, be sure to remove this line:
telnet.StartInf o.CreateNoWindo w = True
so a window will popup for the user to see.
Thanks for the advice but still doesnt work. Is there anyway to send arguments to the telnet session once opened?
Cheers
Plater 7,872
Recognized Expert Expert
I just noticed that you are adding that "o" in there, whereas telnet does not take such arguments.
Try -
telnet.StartInfo.FileName = "telnet.exe"
-
telnet.StartInfo.Arguments = txthostname.text
-
I just noticed that you are adding that "o" in there, whereas telnet does not take such arguments.
Try
-
telnet.StartInfo.FileName = "telnet.exe"
-
telnet.StartInfo.Arguments = txthostname.text
-
Tried this and it opens Telnet but doesnt enter the txthostname.txt argument for me :(
thought the "o" stood for open that why i did that.
Cheers again
Plater 7,872
Recognized Expert Expert
When I run "telnet.exe (some ip address)" it opens and connects for me.
Sorry mate its my fault was entering an IP address in the wrong text box lmao..DOH!
Works a treat thank you very much
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