Hi,
I need to calculate the Cryptographic checksum using ISO/IEC 9797-1 MAC
algorithm with cipher block chaining MAC. The resultant MAC length must be 8 bytes.
As a sample, the data I am working on now is:
Data = '72C29C2371CC9B DB65B779B8E8D37 B29ECC154AA56A8 799FAE2F498F76E D92F2'
Kmac = '7962D9ECE03D1A CD4C76089DCE131 543'
Resultant MAC[Kmac](Data)='5326532 0' (I want to know how to get
to this value using vb.net).
I search this on google but no success for the last 1 week.
Any code?
2  10078 
Hello
You can do it very easy
Divide the key with Key1[ first 64 bits] and key2 [last 64 bits]
use initial vector {0,0,0,0,0,0,0, 0}
divide the message into 8 bytes blocks
pad the last block with "80" and "00","00"," 00" until it reaches 8 bytes
if the message already can be divided by 8, then add another block "80 00 00 00 00 00 00 00"
encrypt by DES CBC algorith with the first key KEY 1
Decrypt the result by DES ECB with the second key KEY2
Encrypt the result by DES ECB with the first key KEY1
take the first 4 bytes as the MAC
Thanks
Mohamed Moustafa
Hi Mohamed,
I need to calculate MAC according to the ISO/IEC 9797-1 Algorithm 1 using DES in CBC mode (the one you talk about is Algorithm 3). Could you tell me how to do that?
Thanks,
Muncho
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