XPath query with node in empty namespace xmlns=""

[olympus_mons]

Hi all,

my XML looks like:

<root xmlns="tempuri. org">
<result xmlns="">
<date>2006-09-14</date>
<status>ok</status>
</result>
</root>

How do I query the status node using .NET 2.0 and XPath?

The only way I found is using local-name():

strState =
xmlDoc.SelectSi ngleNode("//*[local-name()='status']").InnerTex t;

Is there another way?

Thanks for your attention and time,
Stefan

[Bjoern Hoehrmann]

* ol**********@gm x.de wrote in microsoft.publi c.dotnet.xml:

>my XML looks like:

<root xmlns="tempuri. org">
<result xmlns="">
<date>2006-09-14</date>
<status>ok</status>
</result>
</root>

How do I query the status node using .NET 2.0 and XPath?

The only way I found is using local-name():

strState =
xmlDoc.SelectS ingleNode("//*[local-name()='status']").InnerTex t;

Is there another way?

You can setup an XmlNamespaceMan ager as explained in the MSDN docs, and
generally it would be better to use "/root/result/status" instead of the
more complex expression you are using.
--
Björn Höhrmann · mailto:bj****@h oehrmann.de · http://bjoern.hoehrmann.de
Weinh. Str. 22 · Telefon: [phone] · http://www.bjoernsworld.de
68309 Mannheim · PGP Pub. KeyID: 0xA4357E78 · http://www.websitedev.de/

[olympus_mons]

Bjoern,

thanks for your feedback. I got it. It's quite easy with .NET. I first
tested my XPath in XMLSpy and its XPath evaluator seems to have
problems with default and empty NSs. But now I just tried with .NET,
defined a NS "ns" for "tempuri.or g" using the NS manager and then the
XPath just is:

/ns:root/result/status

Stefan
Bjoern Hoehrmann schrieb:

* ol**********@gm x.de wrote in microsoft.publi c.dotnet.xml:

my XML looks like:

<root xmlns="tempuri. org">
<result xmlns="">
<date>2006-09-14</date>
<status>ok</status>
</result>
</root>

How do I query the status node using .NET 2.0 and XPath?

The only way I found is using local-name():

strState =
xmlDoc.SelectSi ngleNode("//*[local-name()='status']").InnerTex t;

Is there another way?

You can setup an XmlNamespaceMan ager as explained in the MSDN docs, and
generally it would be better to use "/root/result/status" instead of the
more complex expression you are using.
--
Björn Höhrmann · mailto:bj****@h oehrmann.de · http://bjoern.hoehrmann.de
Weinh. Str. 22 · Telefon: [phone] · http://www.bjoernsworld..de
68309 Mannheim · PGP Pub. KeyID: 0xA4357E78 · http://www.websitedev.de/

[Martin Honnen]

ol**********@gm x.de wrote:

<root xmlns="tempuri. org">
<result xmlns="">
<date>2006-09-14</date>
<status>ok</status>
</result>
</root>

How do I query the status node using .NET 2.0 and XPath?

The only way I found is using local-name():

strState =
xmlDoc.SelectSi ngleNode("//*[local-name()='status']").InnerTex t;

One way would be the XPath expression /*/result/status e.g.
xmlDoc.SelectSi ngleNode("/*/result/status")
or
xmlDoc.Document Element.SelectS ingleNode("resu lt/status)

--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/