xsl document function - java SimpleTransform cannot find file

[marty.gagnon]

I have a xsl file that references a xml file using the document()
function.
I'm having trouble specifying the URI in the document() function of a
xls stylesheet.

I'm using java to transform the stylesheet, and when it evaluates the
document() function, it cannot find the specified file.

This is how I reference the xml file I'm having trouble with
<xsl:value-of select="documen t('glcodes.xml' ,//)/glcodes/code"/>

I'm using JRun as the web server and I get the following error

SystemId Unknown; Line 1; Column -1; Can not load requested doc:
C:\JRun4\bin\gl codes.xml (The system cannot find the file specified)

I may understand what is going on. The document() function loads the
file (in this case "glcodes.xm l") relative to the xml file used when
the xsl file is transformed. So in my below code, the "xmlSource" is
loaded into memory and used. I guess since JRun is doing the
transformation in memory the relative path is starting at the location
where the Xalan processor has this file in memory which would be
...\JRun4\bin. The question is, how do I modify the URI in the
document() fuction so it's relative to where the xml file is loaded
from.

javax.xml.trans form.Transforme r transformer =
tFactory.newTra nsformer(xslSS) ;
ByteArrayInputS tream baais = new
ByteArrayInputS tream(xmlByteAr ray);
BufferedInputSt ream biis = new BufferedInputSt ream(baais);
StreamSource xmlSource = new StreamSource(bi is);
transformer.tra nsform(xmlSourc e, result);

Thanks
Marty

[Joseph Kesselman]

ma**********@im agenow.com wrote:

I may understand what is going on. The document() function loads the
file (in this case "glcodes.xm l") relative to the xml file used when
the xsl file is transformed.

No, it's relative to the URI at execution time. But you constructed a
StreamSource from a BufferedInputSt ream, which has no obvious base URI
for the StreamSource to use as this starting point. In this situation,
you have to explicitly assert a base URI on the StreamSource before
passing it to the transform() operation. There's a method call for that
purpose.

--
Joe Kesselman / Beware the fury of a patient man. -- John Dryden