XML-like document, want to get attribute names

[ThunderMusic]

Hi,
I have an XML like document I want to parse... The document looks like this
:

<Form id="frmMain" width="345" height="75" HeaderHeight="9 "
image="frmMain. jpg" ColorKey="00000 0">
<Control id="btnTest1" image="btnTest1 .jpg" ColorKey="00000 0" left="10"
top="10" Width="10" Height="10" />
<Control id="btnTest2" image="btnTest2 .jpg" hovertype="beve l" left="50"
top="20" Width="10" Height="10" />
<Control id="pnlTest1" image="pnlTest1 .jpg" ColorKey="00000 0" left="100"
top="30" Width="10" Height="10" />
</Form>

I want to get the attributes names I can get on each element, because right
now I can get everything but the attribute names. here is my code :

FileStream fs = new FileStream(m_Fi lename, FileMode.Open, FileAccess.Read );
XmlReader reader = XmlReader.Creat e(fs);
while (reader.Read())
{
switch (reader.NodeTyp e)
{
case XmlNodeType.Ele ment:
{
if (reader.Name == "Form" || reader.Name == "Control")
{
string NodeKey = string.Empty;
Dictionary<stri ng, objectlst = new Dictionary<stri ng,
object>();
for (int cpt = 0; cpt < reader.Attribut eCount; cpt++)
{
string Key = ""; // HERE'S WHERE I WANT TO KNOW THE NAME
OF THE ATTRIBUTE
string Value = reader.GetAttri bute(cpt)
lst.add(Key, Value);
}
m_Elements.Add( NodeKey, lst);
}
}
break;
}
}

Does anybody know what I should do to get it?

thanks

ThunderMusic

[ThunderMusic]

finally, I found it... thanks to msdn... ;) in my for loop I must do
reader.MoveToAt tribute(cpt) then the reader goes on the attribute and I can
query the name and the value of the attribute using reader.Name and
reader.Value...

thanks

ThunderMusic

"ThunderMus ic" <No************ *************@N oSpAm.comwrote in message
news:Ok******** ******@TK2MSFTN GP04.phx.gbl...

Hi,
I have an XML like document I want to parse... The document looks like
this :

<Form id="frmMain" width="345" height="75" HeaderHeight="9 "
image="frmMain. jpg" ColorKey="00000 0">
<Control id="btnTest1" image="btnTest1 .jpg" ColorKey="00000 0" left="10"
top="10" Width="10" Height="10" />
<Control id="btnTest2" image="btnTest2 .jpg" hovertype="beve l" left="50"
top="20" Width="10" Height="10" />
<Control id="pnlTest1" image="pnlTest1 .jpg" ColorKey="00000 0"
left="100" top="30" Width="10" Height="10" />
</Form>

I want to get the attributes names I can get on each element, because
right now I can get everything but the attribute names. here is my code :

FileStream fs = new FileStream(m_Fi lename, FileMode.Open,
FileAccess.Read );
XmlReader reader = XmlReader.Creat e(fs);
while (reader.Read())
{
switch (reader.NodeTyp e)
{
case XmlNodeType.Ele ment:
{
if (reader.Name == "Form" || reader.Name == "Control")
{
string NodeKey = string.Empty;
Dictionary<stri ng, objectlst = new Dictionary<stri ng,
object>();
for (int cpt = 0; cpt < reader.Attribut eCount; cpt++)
{
string Key = ""; // HERE'S WHERE I WANT TO KNOW THE
NAME OF THE ATTRIBUTE
string Value = reader.GetAttri bute(cpt)
lst.add(Key, Value);
}
m_Elements.Add( NodeKey, lst);
}
}
break;
}
}

Does anybody know what I should do to get it?

thanks

ThunderMusic

[Martin Honnen]

ThunderMusic wrote:

I want to get the attributes names I can get on each element, because right
now I can get everything but the attribute names. here is my code :

FileStream fs = new FileStream(m_Fi lename, FileMode.Open, FileAccess.Read );
XmlReader reader = XmlReader.Creat e(fs);
while (reader.Read())
{
switch (reader.NodeTyp e)
{
case XmlNodeType.Ele ment:
{
if (reader.Name == "Form" || reader.Name == "Control")
{
string NodeKey = string.Empty;
Dictionary<stri ng, objectlst = new Dictionary<stri ng,
object>();

Use a while loop e.g.
while (reader.MoveToN extAttribute()) {
lst.Add(reader. LocalName, reader.Value)
}


--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[ThunderMusic]

thanks... ;) that's a good way too... actually better than mine... ;)
thanks a lot
"Martin Honnen" <ma*******@yaho o.dewrote in message
news:ub******** *****@TK2MSFTNG P02.phx.gbl...

ThunderMusic wrote:

>I want to get the attributes names I can get on each element, because
right now I can get everything but the attribute names. here is my code :

FileStream fs = new FileStream(m_Fi lename, FileMode.Open,
FileAccess.Rea d);
XmlReader reader = XmlReader.Creat e(fs);
while (reader.Read())
{
switch (reader.NodeTyp e)
{
case XmlNodeType.Ele ment:
{
if (reader.Name == "Form" || reader.Name == "Control")
{
string NodeKey = string.Empty;
Dictionary<stri ng, objectlst = new Dictionary<stri ng,
object>();

Use a while loop e.g.
while (reader.MoveToN extAttribute()) {
lst.Add(reader. LocalName, reader.Value)
}


--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/