New to xml - what's wrong with my transform

[-D-]

I'm trying to write my xsl to display an unordered list fromt the xml file
where location is equal to top:

<siteMap xmlns="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0" >
<siteMapNode url="~/index.aspx" title="Home" location="top">
<siteMapNode url="~/about_us/index.aspx" title="About Us" location="top" >
<siteMapNode url="~/about_us/mediaroom.aspx" title="Media Room" />
<siteMapNode url="~/about_us/awards.aspx" title="Awards" />
<siteMapNode url="~/about_us/employment.aspx " title="Employme nt
Opportunities" />
<siteMapNode url="~/about_us/events.aspx" title="Trade Show Calendar" />
<siteMapNode url="~/about_us/partners.aspx" title="Partners and Alliances"
/>
<siteMapNode url="~/about_us/wrcmedia.aspx" title="WRC Media" />
</siteMapNode>
<siteMapNode url="~/contact.aspx" title="Contact Us" location="top" />
<siteMapNode url="http://www.mysite.com" title="Customer Support"
location="top" />
<siteMapNode url="~/sitemap.aspx" title="Site Map" location="top" />
</siteMap>

xsl:

<?xml version="1.0" encoding="utf-8"?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<ul>
<xsl:for-each select="siteMap Node/location/top">
<li>
<a href="{@url}">< xsl:value-of select="@title"/></a>
</li>
</xsl:for-each>
</ul>
</xsl:template>
</xsl:stylesheet>

[Sergey Dubinets]

<xsl:for-each select="siteMap Node[@location = 'top']">

"-D-" <so*****@NOSPAM .comwrote in message
news:u1******** ******@TK2MSFTN GP03.phx.gbl...

I'm trying to write my xsl to display an unordered list fromt the xml file
where location is equal to top:

<siteMap xmlns="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0" >
<siteMapNode url="~/index.aspx" title="Home" location="top">

[-D-]

The transform is still not displaying? Can I use xsl transform on the
default web.sitemap file provided with asp.net 2.0?
"Sergey Dubinets" <sd**@NoSpam.Mi crosoft.comwrot e in message
news:uU******** ******@TK2MSFTN GP02.phx.gbl...

<xsl:for-each select="siteMap Node[@location = 'top']">

"-D-" <so*****@NOSPAM .comwrote in message
news:u1******** ******@TK2MSFTN GP03.phx.gbl...

I'm trying to write my xsl to display an unordered list fromt the xml

file

where location is equal to top:

<siteMap xmlns="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0" >
<siteMapNode url="~/index.aspx" title="Home" location="top">

[Martin Honnen]

-D- wrote:

<siteMap xmlns="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0" >

^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^^ ^^^^^^^^^^^^^^^ ^^^^^^^
You have a namespace declaration here for which you need to account in
your stylesheet and in your XPath expressions and match patterns

<siteMapNode url="~/index.aspx" title="Home" location="top">

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">

xmlns:sm="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0"

<ul>
<xsl:for-each select="siteMap Node/location/top">

<xsl:for-each select="ms:site Map/ms:siteMapNode[@location = 'top']">

--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/

[Sergey Dubinets]

XML you posted is not well formed.

Some siteMapNode are children of other siteMapNode. If you don't want
preserve this hierarch try:
<xsl:for-each select="//siteMapNode[@location = 'top']">

Sergey

"-D-" <so*****@NOSPAM .comwrote in message
news:uD******** ******@TK2MSFTN GP05.phx.gbl...

The transform is still not displaying? Can I use xsl transform on the
default web.sitemap file provided with asp.net 2.0?
"Sergey Dubinets" <sd**@NoSpam.Mi crosoft.comwrot e in message
news:uU******** ******@TK2MSFTN GP02.phx.gbl...

><xsl:for-each select="siteMap Node[@location = 'top']">

"-D-" <so*****@NOSPAM .comwrote in message
news:u1******* *******@TK2MSFT NGP03.phx.gbl.. .

I'm trying to write my xsl to display an unordered list fromt the xml

file

where location is equal to top:

<siteMap xmlns="http://schemas.microso ft.com/AspNet/SiteMap-File-1.0" >
<siteMapNode url="~/index.aspx" title="Home" location="top">