Help - I'm unable to template match on XSL Transform

[jjouett]

I have the following input XML:
<?xml version="1.0"?>
<ordersubmit xmlns:xsd="http ://www.w3.org/2001/XMLSchema"
xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.company.com/webservices/ordersubmit">
<order>
<header>
<ordername>Test Order</ordername>
<start>2006-04-11</start>
</header>
</order>
<request>
<requestaction> SaveAsDraft</requestaction>
</request>
</ordersubmit>
and I need to perform an XSLT such that the result is the following
(changing the namespace structure and reformatting the date:
<ordersubmit xmlns="urn:DGCO rder-schema">
<order>
<header>
<ordername>Test Order</ordername>
<start>04/11/2006</start>
</header>
</order>
<request>
<requestaction> SaveAsDraft</requestaction>
</request>
</ordersubmit>
The following is my current XLST that provides the namespace structure
I need, but I haven't been able to to write a template match that finds
the element named 'start' such that I can reformat the date:
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0" xmlns="urn:DGCO rder-schema">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="@* | node()" />
</xsl:element>
</xsl:template>

</xsl:stylesheet>
Can anyone provide some assistance as to the correct statement to add
to this XSLT to find the 'start' element so I can reformat the date?
Thanks in advance.

[Martin Honnen]

jjouett wrote:

<start>2006-04-11</start> <start>04/11/2006</start>

Add a template
<xsl:template xmlns:os="http://www.company.com/webservices/ordersubmit"
match="os:start ">
<xsl:element name="{local-name()}">
<xsl:value-of select="concat( substring(., 6, 2), '/',
substring(., 9, 2), '/', substring(., 1, 4))" />
</xsl:element>
</xsl:template>
--

Martin Honnen
http://JavaScript.FAQTs.com/

[jjouett]

Works great - thanks!

[swapna guddanti [MSFT]]

you can process the start element by filtering on the name of node as shown
below.

<?xml version="1.0" encoding="utf-8"?>
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0" xmlns="urn:DGCO rder-schema">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:choose>
<xsl:when test="local-name()='start'" >
<!--process your date here-->
<xsl:value-of select="process edDate"/>
</xsl:when>
<xsl:otherwis e>
<xsl:apply-templates select="@* | node()" />
</xsl:otherwise>
</xsl:choose>
</xsl:element>
</xsl:template>
</xsl:stylesheet>
hope this helps,
swapna

"jjouett" <jj*****@necam. com> wrote in message
news:11******** **************@ e56g2000cwe.goo glegroups.com.. .

I have the following input XML:
<?xml version="1.0"?>
<ordersubmit xmlns:xsd="http ://www.w3.org/2001/XMLSchema"
xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
xmlns="http://www.company.com/webservices/ordersubmit">
<order>
<header>
<ordername>Test Order</ordername>
<start>2006-04-11</start>
</header>
</order>
<request>
<requestaction> SaveAsDraft</requestaction>
</request>
</ordersubmit>
and I need to perform an XSLT such that the result is the following
(changing the namespace structure and reformatting the date:
<ordersubmit xmlns="urn:DGCO rder-schema">
<order>
<header>
<ordername>Test Order</ordername>
<start>04/11/2006</start>
</header>
</order>
<request>
<requestaction> SaveAsDraft</requestaction>
</request>
</ordersubmit>
The following is my current XLST that provides the namespace structure
I need, but I haven't been able to to write a template match that finds
the element named 'start' such that I can reformat the date:
<xsl:styleshe et xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
version="1.0" xmlns="urn:DGCO rder-schema">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="*">
<xsl:element name="{local-name()}">
<xsl:apply-templates select="@* | node()" />
</xsl:element>
</xsl:template>

</xsl:stylesheet>
Can anyone provide some assistance as to the correct statement to add
to this XSLT to find the 'start' element so I can reformat the date?
Thanks in advance.

[George Bina]

Just add a template that matches your text node inside a start element
and output the processed date there instead of copying the text node as
it was:

<xsl:template match="text()[parent::o:start]"
xmlns:o="http://www.company.com/webservices/ordersubmit">
<xsl:value-of select="substri ng-before(substrin g-after(., '-'),
'-')"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="substri ng-after(substring-after(., '-'),
'-')"/>
<xsl:text>/</xsl:text>
<xsl:value-of select="substri ng-before(., '-')"/>
</xsl:template>

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com