According to the docs, I would expect to check the result of an
OpenFileDialog in a VS 2005 CLR Windows Forms application this way:
if (openFileDialog 1->ShowDialog() ==
DialogResult::O K)
However, this does not work, and I have to use:
if (openFileDialog 1->ShowDialog() ==
System::Windows ::Forms::Dialog Result::OK)
Did I miss anything, or is this a bug?
Thanks
Richard 11 2659
Hi rk! According to the docs, I would expect to check the result of an OpenFileDialog in a VS 2005 CLR Windows Forms application this way:
if (openFileDialog 1->ShowDialog() == DialogResult::O K)
However, this does not work, and I have to use:
if (openFileDialog 1->ShowDialog() == System::Windows ::Forms::Dialog Result::OK)
Did I miss anything, or is this a bug?
The short-version only works, if you have added
using System::Windows ::Forms;
at the top (or at least before you use the above code).
Or did I miss something in your post?
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
"Jochen Kalmbach [MVP]" <no************ ********@holzma .de> wrote in message
news:u9******** ******@TK2MSFTN GP11.phx.gbl... Hi rk! According to the docs, I would expect to check the result of an OpenFileDialog in a VS 2005 CLR Windows Forms application this way:
if (openFileDialog 1->ShowDialog() == DialogResult::O K)
However, this does not work, and I have to use:
if (openFileDialog 1->ShowDialog() == System::Windows ::Forms::Dialog Result::OK)
Did I miss anything, or is this a bug?
The short-version only works, if you have added
using System::Windows ::Forms;
using namespace System::Windows ::Forms;
that is...
-cd
Hi Jochen,
I had added
using namespace System::Windows ::Forms;
but this did not prevent the problem. I know, that
if (openFileDialog 1->ShowDialog() ==
System::Windows ::Forms::Dialog Result::OK)
and
using namespace System::Windows ::Forms;
if (openFileDialog 1->ShowDialog()== DialogResult::O K)
should be equivalent. So I would expect it to be a bug if they are not.
Or not?
Richard
Jochen Kalmbach [MVP] schrieb: Hi rk! According to the docs, I would expect to check the result of an OpenFileDialog in a VS 2005 CLR Windows Forms application this way:
if (openFileDialog 1->ShowDialog() == DialogResult::O K)
However, this does not work, and I have to use:
if (openFileDialog 1->ShowDialog() == System::Windows ::Forms::Dialog Result::OK)
Did I miss anything, or is this a bug?
The short-version only works, if you have added
using System::Windows ::Forms;
at the top (or at least before you use the above code). Or did I miss something in your post?
Hi rk! using namespace System::Windows ::Forms;
but this did not prevent the problem. I know, that
if (openFileDialog 1->ShowDialog() == System::Windows ::Forms::Dialog Result::OK)
and
using namespace System::Windows ::Forms; if (openFileDialog 1->ShowDialog()== DialogResult::O K)
should be equivalent. So I would expect it to be a bug if they are not.
What prolems do you get???
For me it works without any problems in VS2003 and VS2005...
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
Hi Jochen,
strange. When compiling
private: System::Void openToolStripMe nuItem_Click(Sy stem::Object^
sender, System::EventAr gs^ e) {
if (openFileDialog 1->ShowDialog() == DialogResult::O K)
//System::Windows ::Forms::Dialog Result::OK) // this works
{
richTextBox1->LoadFile(openF ileDialog1->FileName);
}
}
I get
1>c:\vs2005\pro jekt1\projekt1\ Form1.h(156) : error C2039: 'OK': Ist
kein Element von 'System::Window s::Forms::Form: :DialogResult'
1> c:\vs2005\proje kt1\projekt1\Fo rm1.h(23): Siehe Deklaration
von 'System::Window s::Forms::Form: :DialogResult'
1>c:\vs2005\pro jekt1\projekt1\ Form1.h(156) : error C2065: 'OK':
nichtdeklariert er Bezeichner
1>Das Buildprotokoll wurde unter
"file://c:\VS2005\Proje kt1\Projekt1\De bug\BuildLog.ht m" gespeichert.
1>Projekt1 - 2 Fehler, 0 Warnung(en)
If this works for you - what could I have done wrong?
I am using
Microsoft Visual Studio 2005
Version 8.0.50727.42 (RTM.050727-4200)
Microsoft .NET Framework
Version 2.0.50727
Installierte Edition: Professional
Thanks
Richard
Jochen Kalmbach [MVP] schrieb: Hi rk!
using namespace System::Windows ::Forms;
but this did not prevent the problem. I know, that
if (openFileDialog 1->ShowDialog() == System::Windows ::Forms::Dialog Result::OK)
and
using namespace System::Windows ::Forms; if (openFileDialog 1->ShowDialog()== DialogResult::O K)
should be equivalent. So I would expect it to be a bug if they are not.
What prolems do you get??? For me it works without any problems in VS2003 and VS2005...
Hallo R! private: System::Void openToolStripMe nuItem_Click(Sy stem::Object^ sender, System::EventAr gs^ e) {
if (openFileDialog 1->ShowDialog() == DialogResult::O K) { richTextBox1->LoadFile(openF ileDialog1->FileName); } }
I get
1>c:\vs2005\pro jekt1\projekt1\ Form1.h(156) : error C2039: 'OK': Ist kein Element von 'System::Window s::Forms::Form: :DialogResult' 1> c:\vs2005\proje kt1\projekt1\Fo rm1.h(23): Siehe Deklaration von 'System::Window s::Forms::Form: :DialogResult'
Ok! Now I see the problem!
You are using this inside a Form-derived class...
The Form itself contains a member called "DialogResu lt".
The compiler is using this member instead of the enum...
Also if you enter "::" after "DialogResu lt" you get the "correct" hint
(you have only "get" or "set" and no values of the enum!).
AFAIK the shortest version is:
Windows::Forms: :DialogResult:: OK
Inside a Form...
By the way: Es gibt auch eine deutschsprachig e newsgroup für managed C++
/ C++/CLI:
microsoft.publi c.de.german.ent wickler.dotnet. vc
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
Jochen Kalmbach [MVP] schrieb: Hallo R!
private: System::Void openToolStripMe nuItem_Click(Sy stem::Object^ sender, System::EventAr gs^ e) {
if (openFileDialog 1->ShowDialog() == DialogResult::O K) { richTextBox1->LoadFile(openF ileDialog1->FileName); } }
I get
1>c:\vs2005\pro jekt1\projekt1\ Form1.h(156) : error C2039: 'OK': Ist kein Element von 'System::Window s::Forms::Form: :DialogResult' 1> c:\vs2005\proje kt1\projekt1\Fo rm1.h(23): Siehe Deklaration von 'System::Window s::Forms::Form: :DialogResult' Ok! Now I see the problem! You are using this inside a Form-derived class... The Form itself contains a member called "DialogResu lt".
Thanks, that would be an explanation.
But where does this member come from? I have not inserted it.
The compiler is using this member instead of the enum...
Also if you enter "::" after "DialogResu lt" you get the "correct" hint (you have only "get" or "set" and no values of the enum!).
AFAIK the shortest version is: Windows::Forms: :DialogResult:: OK
Inside a Form...
By the way: Es gibt auch eine deutschsprachig e newsgroup für managed C++ / C++/CLI: microsoft.publi c.de.german.ent wickler.dotnet. vc
Vielen Dank
Richard Kaiser
Hallo R! Ok! Now I see the problem! You are using this inside a Form-derived class... The Form itself contains a member called "DialogResu lt".
Thanks, that would be an explanation.
But where does this member come from? I have not inserted it.
It is a member of the "Form"-class: http://msdn2.microsoft.com/en-us/lib...logresult.aspx
Also in the example they use
::DialogResult: :OK
as a shortcut... but it does not compile...
Maybe there is a shorted way; but I do not know it currently...
--
Greetings
Jochen
My blog about Win32 and .NET http://blog.kalmbachnet.de/
Jochen Kalmbach [MVP] schrieb: Hallo R!
Ok! Now I see the problem! You are using this inside a Form-derived class... The Form itself contains a member called "DialogResu lt".
Thanks, that would be an explanation.
But where does this member come from? I have not inserted it.
It is a member of the "Form"-class: http://msdn2.microsoft.com/en-us/lib...logresult.aspx
Also in the example they use ::DialogResult: :OK as a shortcut... but it does not compile...
Maybe there is a shorted way; but I do not know it currently...
Vielen Dank
Richard Kaiser This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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