How to resolve a XPath in XSLT

John Henckel

I have a data file like this.....

<top>
<graph>
<part>
<param name="mass">1 </param>
</part>
<body name="nut">
<link href="#/top/graph['1']/part['1']"/>
</body>
</graph>
</top>

Notice the "link" is a path to another node in the file. I want to use
XSLT to process this file to print a table with the name of each body
and it's mass. But I cannot figure out how to do it. This is what I
tried......

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="top//body">

<p/> <xsl:value-of select="@name"/> has mass
<xsl:variable name="var" select="substri ng(link/@href,2)"/>
<xsl:value-of select="$var/param"/>

</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
But this doesn't work because it says $var/param is a syntax error. Any
ideas? Am I trying to do the impossible? I do not have any control of
the input data representation.

TIA, john

Feb 2 '06 #1

Subscribe Reply

1593

Martin Honnen

John Henckel wrote:

Notice the "link" is a path to another node in the file. I want to use
XSLT to process this file to print a table with the name of each body
and it's mass.

There is no dynamic XPath evaluation in XSLT unless your processor
provides an extension function e.g. like Saxon here
<http://saxon.sourcefor ge.net/saxon6.5.5/extensions.html #evaluate>

--

Martin Honnen
http://JavaScript.FAQTs.com/

Feb 2 '06 #2

Soren Kuula

Martin Honnen wrote:

John Henckel wrote:

Notice the "link" is a path to another node in the file. I want to
use XSLT to process this file to print a table with the name of each
body and it's mass.

There is no dynamic XPath evaluation in XSLT unless your processor
provides an extension function e.g. like Saxon here
<http://saxon.sourcefor ge.net/saxon6.5.5/extensions.html #evaluate>

I suppose this one could be resolved by generating an XSL stylesheet
using XSL (or whatever...), stuffing in the XPath there, and then
executing that on the original document.

There is a prefix anti-aliasing feature, of which I can never remember
the name, to enable you to write stylesheet-spewing stylesheets
(distinguish output from instructions)

Soren

Feb 2 '06 #3

Martin Honnen

Soren Kuula wrote:

I suppose this one could be resolved by generating an XSL stylesheet
using XSL (or whatever...), stuffing in the XPath there, and then
executing that on the original document.

Yes, that is also possible, most things done by an extension function
you can be solved without it by doing two or more transformation steps.
--

Martin Honnen
http://JavaScript.FAQTs.com/

Feb 3 '06 #4

Joseph Kesselman

> There is no dynamic XPath evaluation in XSLT unless your processor

provides an extension function

The "semi-standard" dynamic XPath extension is the one in the EXSLT
library. Some processors ship with part or all of EXSLT, some don't.
Check the docs.

Another solution is to use a stylesheet to generate a stylesheet with
your desired XPath, then apply that stylesheet as a separate pass.
--
Joe Kesselman / Beware of Blueshift!
(And don't confuse an institution's stated values with its policies.)

Feb 3 '06 #5

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