Multiple web service classes in a single URL

[Howard Postley]

This seems like it's probably a pretty basic question but is there a way to
publish multiple classes from a single web service URL?

Using VS.NET, I create a project, FOO and add a web service, BAR, to it with
one function, baz(). Then, I create a second project to consume the service.
I add a web reference to http://webserver/FOO/BAR.asmx and call that,
BAR_Service. In the code, if I do something like:

dim ws as new BAR_Service.BAR
ws.baz()

My questions are:
Is there a way to add a second class to the web service that could be
referenced as, say, BAR_Service.BAR 2? If not, why is the one and only class
that can be referenced by the web service not implicit in the reference to
the service?

Thanks for any help,

</hjp>

[NuTcAsE]

Yes you can add a second web service using the Add new item dialog in
VS. Say you a new web service named BOO with one function boo. After
doing so, update the web reference in your client project, your
BAR_Service will contain the following:

BAR_Service.BAR ws1 = new BAR_Service.BAR ()
ws1.baz();
BAR_Service.BOO ws2 = new BAR_Service.BOO ();
ws2.boo ();

Hope this helps...

- NuTcAsE

[Howard Postley]

That's what I thought should happen, as well. Alas... Each newly added web
service adds a new .asmx file. That .asmx file corresponds to an URL. Hence,
you have to add two references to the consuming app, one to
http://server/BAR.asmx (called BAR_Service) and a second one to
http://server/BOO.asmx (called BOO_Service) and then reference them:

BAR_Service.BAR ws1 = new BAR_Service.BAR ()

and

BOO_Service.BOO ws2 = new BOO_Service.BOO ()

I can find no way to add a single URL to the consuming app (called Service)
such that Service.BAR and Service.BOO are accessible.

"NuTcAsE" wrote:

Yes you can add a second web service using the Add new item dialog in
VS. Say you a new web service named BOO with one function boo. After
doing so, update the web reference in your client project, your
BAR_Service will contain the following:

BAR_Service.BAR ws1 = new BAR_Service.BAR ()
ws1.baz();
BAR_Service.BOO ws2 = new BAR_Service.BOO ();
ws2.boo ();

Hope this helps...

- NuTcAsE