How do I preserve XML tags in XSLT transform

[Andrew Jocelyn]

Hi

Is there a way of outputting some xml tags during an XSLT transform? For
example when I use the 'xsl:value-of select="xhtml"' statement I'd like to
output the children of 'xhtml' after the transform. At the moment the tags
are being ignored. I don't want to put the contents inside CDATA because I
want to be able to parse the xml file as proper xml elsewhere in the
application.

<contentItem>
<title>Stuff about the content</title>
<xhtml>
<h1>Heading</h1>
<p>Para1</p>
<p>Para2</p>
<p>Para3</p>
</xhtml>
</contentItem>

<xsl:output indent="yes" method="xml"
doctype-system="http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"
doctype-public="-//W3C//DTD XHTML 1.0 Strict//EN"/>
<xsl:template match="contentI tem">
<title><xsl:val ue-of select="title"/></title>
<xsl:value-of select="xhtml" disable-output-escaping="yes"/>
</xsl:template>

Many thanks
Andrew

[Oleg Tkachenko [MVP]]

Andrew Jocelyn wrote:

Is there a way of outputting some xml tags during an XSLT transform? For
example when I use the 'xsl:value-of select="xhtml"' statement I'd like to
output the children of 'xhtml' after the transform. At the moment the tags
are being ignored.

Because you are using xsl:value-of which by definition outputs string
value. Use <xsl:copy-of> instead.

--
Oleg Tkachenko [XML MVP, MCAD]
http://www.XmlLab.Net | http://www.XLinq.Net | http://blog.tkachenko.com

[Andrew Jocelyn]

Great, thanks for that. I'm new to this as you can probably tell.

I'm getting the xml namespace attribute added in the output now. Do you know
what controls that?

<p xmlns=""></p>

Thanks again.
Andrew
"Oleg Tkachenko [MVP]" <so**@body.co m> wrote in message
news:43******** ******@body.com ...

Andrew Jocelyn wrote:

Is there a way of outputting some xml tags during an XSLT transform? For
example when I use the 'xsl:value-of select="xhtml"' statement I'd like
to output the children of 'xhtml' after the transform. At the moment the
tags are being ignored.

Because you are using xsl:value-of which by definition outputs string
value. Use <xsl:copy-of> instead.

--
Oleg Tkachenko [XML MVP, MCAD]
http://www.XmlLab.Net | http://www.XLinq.Net | http://blog.tkachenko.com

[Martin Honnen]

Andrew Jocelyn wrote:

I'm getting the xml namespace attribute added in the output now. Do you know
what controls that?

<p xmlns=""></p>

If you use xsl:copy-of the element is copied as it is from the input
tree. With the above output I guess your p element in the input was in
no namespace, is copied to the result tree as an element in no namespace
and the serializer which serializes the result tree has to add the
xmlns="" to properly serialize the element.
So either make sure that the input tree defines the namespace you want e.g.
<p xmlns="http://www.w3.org/1999/xhtml">
or your stylesheet processes p elements in no namespace and produces
XHTML elements e.g.
<xsl:template match="p">
<xsl:element name="{local-name()}"
namespace="http ://www.w3.org/1999/xhtml">
<xsl:apply-templates select="@* | node()" />
</xsl:element>
</xsl:template>
Then you can't use xsl:copy but need to use
<xsl:apply-templates />
--

Martin Honnen --- MVP XML
http://JavaScript.FAQTs.com/