Throwing exceptions in finally block

[Sean Kelly]

I'm curious about the reason for the current behavior. I modified the
MSDN C# sample code like so:

try
{
try
{
int[] array1={0,0};
int[] array2={0,0};
Array.Copy(arra y1,array2,-1);
}
finally
{
Console.WriteLi ne("This statement is always executed.");
throw new Exception("die" );
}
}
catch (ArgumentOutOfR angeException e)
{
Console.WriteLi ne("Error: {0}",e);
}
catch (Exception e)
{
Console.WriteLi ne("Error: {0}\n",e);
Console.WriteLi ne("Error: {0}\n",e.InnerE xception);
}

The result of the above code is that the ArgumentOutOfRa ngeException
is lost and catch(Exception ) is called for "die." I assume the
behavior would be the same in C++. So what is the reason for dropping
the original exception? Being a C++ person, I half expected the
application to terminate when I threw the second exception.
Sean