I have the following Schema (XMLSchema1.xsd ):
<?xml version="1.0" encoding="utf-8" ?>
<xs:schema id="XMLSchema1 "
targetNamespace ="http://tempuri.org/XMLSchema1.xsd"
elementFormDefa ult="qualified"
xmlns="http://tempuri.org/XMLSchema1.xsd"
xmlns:mstns="ht tp://tempuri.org/XMLSchema1.xsd"
xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:simpleTyp e name="FruitType ">
<xs:annotatio n>
<xs:appinfo>H as a color</xs:appinfo>
</xs:annotation>
<xs:restricti on base="xs:string ">
<xs:enumerati on value="Apple">
<xs:annotatio n>
<xs:appinfo>I s green</xs:appinfo>
</xs:annotation>
</xs:enumeration>
<xs:enumerati on value="Oranges" >
<xs:annotatio n>
<xs:appinfo>I s orange</xs:appinfo>
</xs:annotation>
</xs:enumeration>
</xs:restriction>
</xs:simpleType>
<xs:element name="Bowl">
<xs:complexType >
<xs:sequence>
<xs:element name="Fruit" type="FruitType " maxOccurs="unbo unded"/>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:schema>
the following Xml (XMLFile1.xml):
<?xml version="1.0" encoding="utf-8" ?>
<Bowl xmlns="http://tempuri.org/XMLSchema1.xsd"
xmlns:xsi="http ://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocat ion="http://tempuri.org/XMLSchema1.xsd
XMLSchema1.xsd" >
<Fruit>Apple</Fruit>
</Bowl>
And the following code:
XmlSchema schema;
using (Stream s =
(Assembly.GetEx ecutingAssembly ().GetManifestR esourceStream(" WindowsApplicat ion10.XMLSchema 1.xsd")))
{
schema = XmlSchema.Read( s, null);
}
XmlDocument doc;
using (Stream s =
(Assembly.GetEx ecutingAssembly ().GetManifestR esourceStream(" WindowsApplicat ion10.XMLFile1. xml")))
{
doc = new XmlDocument();
doc.Load(s);
doc.Schemas.Add (schema);
doc.Schemas.Com pile();
doc.Validate(nu ll);
}
if (doc != null && schema != null) {
XmlNamespaceMan ager nsmgr = new XmlNamespaceMan ager(doc.NameTa ble);
nsmgr.AddNamesp ace("rpt", "http://tempuri.org/XMLSchema1.xsd" );
XmlNodeList viewNodes = doc.SelectNodes ("rpt:Bowl/rpt:Fruit",
nsmgr);
foreach (XmlElement viewElem in viewNodes) {
string id = viewElem.InnerT ext;
System.Xml.Sche ma.IXmlSchemaIn fo si = viewElem.Schema Info;
XmlSchemaAnnota tion ann = si.SchemaType.A nnotation;
if (ann != null) {
XmlSchemaAppInf o ai = ann.Items[0] as XmlSchemaAppInf o;
Console.WriteLi ne("The type has annotation: " +
ai.Markup[0].Value);
}
XmlSchemaSimple Type st = si.SchemaType as XmlSchemaSimple Type;
ann = st.Content.Anno tation;
if (ann != null) {
XmlSchemaAppInf o ai = ann.Items[0] as XmlSchemaAppInf o;
Console.WriteLi ne("The enum has annotation: " +
ai.Markup[0].Value);
}
}
}
The annotation for FruitType comes back correctly as 'Has a color', but
there seems to be no annotation available for the actual enum value
itself. Is this a bug? Is there another way to get the annotation of an
enumeration (value)? 1 2282
Never mind. I found the answer:
foreach (XmlElement viewElem in viewNodes) {
string id = viewElem.InnerT ext;
System.Xml.Sche ma.IXmlSchemaIn fo si = viewElem.Schema Info;
XmlSchemaAnnota tion ann = si.SchemaType.A nnotation;
if (ann != null) {
XmlSchemaAppInf o ai = ann.Items[0] as XmlSchemaAppInf o;
Console.WriteLi ne("The type has annotation: " +
ai.Markup[0].Value);
}
XmlSchemaSimple Type st = si.SchemaType as XmlSchemaSimple Type;
XmlSchemaSimple TypeRestriction str = st.Content as
XmlSchemaSimple TypeRestriction ;
foreach (XmlSchemaEnume rationFacet facet in str.Facets) {
ann = facet.Annotatio n;
if (ann != null) {
XmlSchemaAppInf o ai = ann.Items[0] as XmlSchemaAppInf o;
Console.WriteLi ne("The enum has annotation: " +
ai.Markup[0].Value);
}
}
} This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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