I am trying to write an application that will generate XSL files
(trying to automat some of my development), but am having a heck of a
time. I just don't fully grasp the namespace issues I am having.
This is what I have so far:
---------------------------------Code
XmlDocument doc = new XmlDocument();
doc.AppendChild (doc.CreateXmlD eclaration
("1.0","UTF-8", string.Empty));
XmlNode root = doc.AppendChild (doc.CreateElem ent
("xsl:styleshee t","http://www.w3.org/1999/XSL/Transform"));
XmlAttribute attr = doc.CreateAttri bute("version") ;
attr.InnerText = "1.0";
root.Attributes .Append(attr);
---------------------------------/Code
That results into this:
---------------------------------Results
<?xml version="1.0" encoding="UTF-8"?>
<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform">
</xsl:stylesheet>
----------------------------------/Results
Not to bad, but I run into problems here:
---------------------------------Code
root = root.AppendChil d(doc.CreateEle ment
("xsl","templat e", "xsl"));
--------------------------------/Code
This gives me an element that looks like this:
---------------------------------Results
<xsl:template xmlns:xsl="xsl"/>
---------------------------------/Results
Am I doing this correctly? That 'xmlns:xsl="xsl "' I don't want there.
But if I try other combination of values (("xsl","templa te") ||
("xsl:template" ) || ("xsl","templat e","")) I never get the
"xsl:templa te", just "template".
Am I making sense?
Is there a better, or right why to do something like this (Besides
string builder)? What am I doing wrong?
To the one that helps me with this problem I will give you an invisible
ring of +6 save against coding errors. (ooooo, awwwww) 5 2590
Hi,
You need to specify the URI of the 'xsl' namespace in the third argument of
CreateElement.
That is,
root = root.AppendChil d(doc.CreateEle ment
("xsl","templat e", "http://www.w3.org/1999/XSL/Transform"));
--
Sincerely,
Dmytro Lapshyn [Visual Developer - Visual C# MVP]
"skidz" <ro************ *@gmail.com> wrote in message
news:11******** **************@ z14g2000cwz.goo glegroups.com.. . I am trying to write an application that will generate XSL files (trying to automat some of my development), but am having a heck of a time. I just don't fully grasp the namespace issues I am having.
This is what I have so far: ---------------------------------Code XmlDocument doc = new XmlDocument(); doc.AppendChild (doc.CreateXmlD eclaration ("1.0","UTF-8", string.Empty)); XmlNode root = doc.AppendChild (doc.CreateElem ent ("xsl:styleshee t","http://www.w3.org/1999/XSL/Transform")); XmlAttribute attr = doc.CreateAttri bute("version") ; attr.InnerText = "1.0"; root.Attributes .Append(attr); ---------------------------------/Code
That results into this: ---------------------------------Results <?xml version="1.0" encoding="UTF-8"?> <xsl:styleshe et version="1.0" xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"> </xsl:stylesheet> ----------------------------------/Results
Not to bad, but I run into problems here: ---------------------------------Code root = root.AppendChil d(doc.CreateEle ment ("xsl","templat e", "xsl")); --------------------------------/Code
This gives me an element that looks like this: ---------------------------------Results <xsl:template xmlns:xsl="xsl"/> ---------------------------------/Results
Am I doing this correctly? That 'xmlns:xsl="xsl "' I don't want there. But if I try other combination of values (("xsl","templa te") || ("xsl:template" ) || ("xsl","templat e","")) I never get the "xsl:templa te", just "template". Am I making sense?
Is there a better, or right why to do something like this (Besides string builder)? What am I doing wrong?
To the one that helps me with this problem I will give you an invisible ring of +6 save against coding errors. (ooooo, awwwww)
This is quite masochistic compared to generating xslt stylesheets using ...
XSLT.
Cheers,
Dimitre Novatchev.
"skidz" <ro************ *@gmail.com> wrote in message
news:11******** **************@ z14g2000cwz.goo glegroups.com.. . I am trying to write an application that will generate XSL files (trying to automat some of my development), but am having a heck of a time. I just don't fully grasp the namespace issues I am having.
This is what I have so far: ---------------------------------Code XmlDocument doc = new XmlDocument(); doc.AppendChild (doc.CreateXmlD eclaration ("1.0","UTF-8", string.Empty)); XmlNode root = doc.AppendChild (doc.CreateElem ent ("xsl:styleshee t","http://www.w3.org/1999/XSL/Transform")); XmlAttribute attr = doc.CreateAttri bute("version") ; attr.InnerText = "1.0"; root.Attributes .Append(attr); ---------------------------------/Code
That results into this: ---------------------------------Results <?xml version="1.0" encoding="UTF-8"?> <xsl:styleshe et version="1.0" xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"> </xsl:stylesheet> ----------------------------------/Results
Not to bad, but I run into problems here: ---------------------------------Code root = root.AppendChil d(doc.CreateEle ment ("xsl","templat e", "xsl")); --------------------------------/Code
This gives me an element that looks like this: ---------------------------------Results <xsl:template xmlns:xsl="xsl"/> ---------------------------------/Results
Am I doing this correctly? That 'xmlns:xsl="xsl "' I don't want there. But if I try other combination of values (("xsl","templa te") || ("xsl:template" ) || ("xsl","templat e","")) I never get the "xsl:templa te", just "template". Am I making sense?
Is there a better, or right why to do something like this (Besides string builder)? What am I doing wrong?
To the one that helps me with this problem I will give you an invisible ring of +6 save against coding errors. (ooooo, awwwww)
Dmytro Lapshyn, Thx I will give that a try. I will email you the ring
as soon as I find it. :)
Dimitre Novatchev, I thought about doing that, but how do you escape
the xsl nodes you want to output, so they are not executed in the
transformation? I have never tried it so if the question is stupid you
have my permission to slap me.
"skidz" <ro************ *@gmail.com> wrote in message
news:11******** **************@ g14g2000cwa.goo glegroups.com.. . Dmytro Lapshyn, Thx I will give that a try. I will email you the ring as soon as I find it. :)
Dimitre Novatchev, I thought about doing that, but how do you escape the xsl nodes you want to output, so they are not executed in the transformation? I have never tried it so if the question is stupid you have my permission to slap me.
No the question is not stupid.
Read about the
"xsl:namesp ace-alias"
element.
Cheers,
Dimitre Novatchev
Dimitre Novatchev, That is perfect. I tried searching google for xsl to
xsl and could never find anything good. Thx
I can now stop being so masochistic.
Dmytro Lapshyn, your solution worked great also. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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