I'm finding the XmlSchema object model very hard to follow :-(
I've figured out by trial and error how to do most things I need,
but this one has me beat.
Suppose my schema has a simple type defined as follows:
<xs:simpleTyp e name="abc">
<xs:restricti on base="xs:string ">
<xs:enumerati on value="A" />
<xs:enumerati on value="B" />
<xs:enumerati on value="C" />
</xs:restriction>
</xs:simpleType>
Now suppose one of my elements has an attribute whose type
is the "abc" type shown above, as in:
<xs:attribute name="attribute 1" type="abc" />
If I navigate through the SOM to find the attribute,
my XmlSchemaAttrib ute object will have its SchemaTypeName. Name
property set to "abc".
My question is: how do I find out the basic type of the
attribute? I simply want to know that it's based on the
xs:string built-in type, but I can't find any way to
do that using the SOM... 2 1660
Hi Gary
How about this. Reads the schema, gets a simple type whose name is abc, then
looks at the base type.
HTH
Nigel Armstrong
Dim fs As New IO.FileStream(" C:\test.xsd", IO.FileMode.Ope n)
Dim s As Xml.Schema.XmlS chema = Xml.Schema.XmlS chema.Read(fs, Nothing)
s.Compile(Nothi ng)
fs.Close()
Dim ot As Xml.Schema.XmlS chemaObjectTabl e = s.SchemaTypes
Dim st As Xml.Schema.XmlS chemaSimpleType = CType(ot.Item(N ew
Xml.XmlQualifie dName("abc")), Xml.Schema.XmlS chemaSimpleType )
MessageBox.Show (st.BaseSchemaT ype.ToString())
"Gary McGill" wrote: I'm finding the XmlSchema object model very hard to follow :-(
I've figured out by trial and error how to do most things I need, but this one has me beat.
Suppose my schema has a simple type defined as follows:
<xs:simpleTyp e name="abc"> <xs:restricti on base="xs:string "> <xs:enumerati on value="A" /> <xs:enumerati on value="B" /> <xs:enumerati on value="C" /> </xs:restriction> </xs:simpleType>
Now suppose one of my elements has an attribute whose type is the "abc" type shown above, as in:
<xs:attribute name="attribute 1" type="abc" />
If I navigate through the SOM to find the attribute, my XmlSchemaAttrib ute object will have its SchemaTypeName. Name property set to "abc".
My question is: how do I find out the basic type of the attribute? I simply want to know that it's based on the xs:string built-in type, but I can't find any way to do that using the SOM...
Nigel,
I tried that, but what it actually gets is the name of the .NET class used
to represent the type (such as System.Xml.Sche ma.Datatype_str ing") rather
than the qualified name of the type (such as "string" or "positiveIntege r").
I suppose I could use the bit after the "_" but that sounds ugly - surely
there must be a better way?
Gary
"Nigel Armstrong" <Ni************ @discussions.mi crosoft.com> wrote in
message news:FF******** *************** ***********@mic rosoft.com... Hi Gary
How about this. Reads the schema, gets a simple type whose name is abc,
then looks at the base type.
HTH
Nigel Armstrong
Dim fs As New IO.FileStream(" C:\test.xsd", IO.FileMode.Ope n) Dim s As Xml.Schema.XmlS chema = Xml.Schema.XmlS chema.Read(fs, Nothing) s.Compile(Nothi ng) fs.Close() Dim ot As Xml.Schema.XmlS chemaObjectTabl e = s.SchemaTypes Dim st As Xml.Schema.XmlS chemaSimpleType = CType(ot.Item(N ew Xml.XmlQualifie dName("abc")), Xml.Schema.XmlS chemaSimpleType ) MessageBox.Show (st.BaseSchemaT ype.ToString())
"Gary McGill" wrote:
I'm finding the XmlSchema object model very hard to follow :-(
I've figured out by trial and error how to do most things I need, but this one has me beat.
Suppose my schema has a simple type defined as follows:
<xs:simpleTyp e name="abc"> <xs:restricti on base="xs:string "> <xs:enumerati on value="A" /> <xs:enumerati on value="B" /> <xs:enumerati on value="C" /> </xs:restriction> </xs:simpleType>
Now suppose one of my elements has an attribute whose type is the "abc" type shown above, as in:
<xs:attribute name="attribute 1" type="abc" />
If I navigate through the SOM to find the attribute, my XmlSchemaAttrib ute object will have its SchemaTypeName. Name property set to "abc".
My question is: how do I find out the basic type of the attribute? I simply want to know that it's based on the xs:string built-in type, but I can't find any way to do that using the SOM... This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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