node-sets not sent to xslt extension object correctly

[Douglas Steen]

Here's what I have (in snippets)
** XML **
<parent>
<child>
<grandchild/>
</child>
</parent>

** XSLT **
<xsl:template match="/parent">
parent: <xsl:value-of select="util:Lo calName(.)"/>
child: <xsl:value-of select="util:Lo calName(child)"/>
grandchild: <xsl:value-of select="util:Lo calName(child/grandchild)"/>
</xsl:template>

** C# (util object) **
public string LocalName(XmlPa thNodeIterator xit)
{
return xit.Current.Loc alName;
}

but for some reason, each call to LocalName returns "parent". A little
sleuthing, and I've discovered that the XmlPathNodeIter ators _are_
different: they seem to have different FilterQuery and ChildrenQuery
internal settings, but how do I translate that into something I can have
access to?

Thanks,
Douglas R. Steen
Boulder, CO

[Oleg Tkachenko [MVP]]

Douglas Steen wrote:

public string LocalName(XmlPa thNodeIterator xit)
{
return xit.Current.Loc alName;
}

You have to call MoveNext() on XPathNodeIterat or each time you want next
node:

public string LocalName(XPath NodeIterator xit)
{
if (xit.MoveNext() )
return xit.Current.Loc alName;
else
return "";
}

--
Oleg Tkachenko [XML MVP]
http://blog.tkachenko.com

[Douglas Steen]

Thanks, Oleg, but when I try that with the first example (XSLT:
select="util:Lo calName(.)") it returns false and .Current becomes null.
It's as if, in the first example, the iterator has already been "moved". Is
it that calling the extension object with (.) sends the XPathNodeIterat or
with a single node, whereas calling it with (child) sends a nodeset? If so,
is there a way of telling that MoveNext is going to move me off the end of
the set, before I move? (Or, even better, changing my XSLT so that I can be
sure that a single node is sent? I've tried /child[0] and /child/node() to
no avail.)

Thanks alot for the help.

"Oleg Tkachenko [MVP]" <oleg@NO!SPAM!P LEASEtkachenko. com> wrote in message
news:un******** ********@TK2MSF TNGP11.phx.gbl. ..

Douglas Steen wrote:

public string LocalName(XmlPa thNodeIterator xit)
{
return xit.Current.Loc alName;
}

You have to call MoveNext() on XPathNodeIterat or each time you want next
node:

public string LocalName(XPath NodeIterator xit)
{
if (xit.MoveNext() )
return xit.Current.Loc alName;
else
return "";
}

--
Oleg Tkachenko [XML MVP]
http://blog.tkachenko.com

[Oleg Tkachenko [MVP]]

Douglas Steen wrote:

Thanks, Oleg, but when I try that with the first example (XSLT:
select="util:Lo calName(.)") it returns false and .Current becomes null.
It's as if, in the first example, the iterator has already been "moved". Is
it that calling the extension object with (.) sends the XPathNodeIterat or
with a single node, whereas calling it with (child) sends a nodeset? If so,
is there a way of telling that MoveNext is going to move me off the end of
the set, before I move? (Or, even better, changing my XSLT so that I can be
sure that a single node is sent? I've tried /child[0] and /child/node() to
no avail.)

Sorry, I can't reproduce the problem. Here is the stylesheet:

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="ur n:schemas-microsoft-com:xslt" xmlns:util="urn :my-scripts">
<msxsl:script language="C#" implements-prefix="util">< ![CDATA[
public string LocalName(XPath NodeIterator xit)
{
return xit.MoveNext()? xit.Current.Loc alName : "";
}
]]>
</msxsl:script>
<xsl:template match="/parent">
parent: <xsl:value-of select="util:Lo calName(.)"/>
child: <xsl:value-of select="util:Lo calName(child)"/>
grandchild: <xsl:value-of select="util:Lo calName(child/grandchild)"/>
</xsl:template>
</xsl:stylesheet>

When applied to your XML it outputs:

parent: parent
child: child
grandchild: grandchild

--
Oleg Tkachenko [XML MVP]
http://blog.tkachenko.com

[Douglas Steen]

I'm using a rather complicated extension object (rather than doing it
inline), and in simplifying for this post, I may have gone too far. I used
your example and got the same results, but when I tried to add some of the
initial complexity, I ran into the problem again. While the example below
works, this one doesn't:

<xsl:template match="/parent">
<xsl:for-each select="child">
parent: <xsl:value-of select="util:Lo calName(../parent)"/>
child: <xsl:value-of select="util:Lo calName(.)"/>
grandchild: <xsl:value-of select="util:Lo calName(./grandchild)"/>
</xsl:for-each>
</xsl:template>

Thoughts?

Thanks for taking the time on this
"Oleg Tkachenko [MVP]" <oleg@NO!SPAM!P LEASEtkachenko. com> wrote in message
news:OC******** ******@TK2MSFTN GP10.phx.gbl...

Douglas Steen wrote:

Thanks, Oleg, but when I try that with the first example (XSLT:
select="util:Lo calName(.)") it returns false and .Current becomes null.
It's as if, in the first example, the iterator has already been "moved". Is it that calling the extension object with (.) sends the XPathNodeIterat or with a single node, whereas calling it with (child) sends a nodeset? If so, is there a way of telling that MoveNext is going to move me off the end of the set, before I move? (Or, even better, changing my XSLT so that I can be sure that a single node is sent? I've tried /child[0] and /child/node() to no avail.)

Sorry, I can't reproduce the problem. Here is the stylesheet:

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="ur n:schemas-microsoft-com:xslt" xmlns:util="urn :my-scripts">
<msxsl:script language="C#" implements-prefix="util">< ![CDATA[
public string LocalName(XPath NodeIterator xit)
{
return xit.MoveNext()? xit.Current.Loc alName : "";
}
]]>
</msxsl:script>
<xsl:template match="/parent">
parent: <xsl:value-of select="util:Lo calName(.)"/>
child: <xsl:value-of select="util:Lo calName(child)"/>
grandchild: <xsl:value-of select="util:Lo calName(child/grandchild)"/>
</xsl:template>
</xsl:stylesheet>

When applied to your XML it outputs:

parent: parent
child: child
grandchild: grandchild

--
Oleg Tkachenko [XML MVP]
http://blog.tkachenko.com

[Douglas Steen]

On a hunch, I tried this:

<xsl:template match="/parent">
<xsl:variable name="parentNod e" select="."/>
<xsl:for-each select="child">
parent: <xsl:value-of select="util:Lo calName($parent Node)"/>
child: <xsl:value-of select="util:Lo calName(.)"/>
grandchild: <xsl:value-of select="util:Lo calName(./grandchild)"/>
</xsl:for-each>
</xsl:template>

and it _does_ work. Whereas calling the parent directly (..) doesn't?

Alright, now I've got something I can use; thanks for all your help. If you
(or anyone else) wants to clear up what's going on here, I'd love to
understand this better, but I can move forward now & I thank you.

"Douglas Steen" <du*@pobox.co m> wrote in message
news:%2******** ********@TK2MSF TNGP11.phx.gbl. ..

I'm using a rather complicated extension object (rather than doing it
inline), and in simplifying for this post, I may have gone too far. I used your example and got the same results, but when I tried to add some of the
initial complexity, I ran into the problem again. While the example below
works, this one doesn't:

<xsl:template match="/parent">
<xsl:for-each select="child">
parent: <xsl:value-of select="util:Lo calName(../parent)"/>
child: <xsl:value-of select="util:Lo calName(.)"/>
grandchild: <xsl:value-of select="util:Lo calName(./grandchild)"/>
</xsl:for-each>
</xsl:template>

Thoughts?

Thanks for taking the time on this
"Oleg Tkachenko [MVP]" <oleg@NO!SPAM!P LEASEtkachenko. com> wrote in message
news:OC******** ******@TK2MSFTN GP10.phx.gbl...

Douglas Steen wrote:

Thanks, Oleg, but when I try that with the first example (XSLT:
select="util:Lo calName(.)") it returns false and .Current becomes null. It's as if, in the first example, the iterator has already been

"moved".

Is it that calling the extension object with (.) sends the XPathNodeIterat or with a single node, whereas calling it with (child) sends a nodeset?

If

so, is there a way of telling that MoveNext is going to move me off the

end

of the set, before I move? (Or, even better, changing my XSLT so that I can be sure that a single node is sent? I've tried /child[0] and

/child/node()

to no avail.)

Sorry, I can't reproduce the problem. Here is the stylesheet:

<xsl:styleshe et version="1.0"
xmlns:xsl="http ://www.w3.org/1999/XSL/Transform"
xmlns:msxsl="ur n:schemas-microsoft-com:xslt" xmlns:util="urn :my-scripts"> <msxsl:script language="C#" implements-prefix="util">< ![CDATA[
public string LocalName(XPath NodeIterator xit)
{
return xit.MoveNext()? xit.Current.Loc alName : "";
}
]]>
</msxsl:script>
<xsl:template match="/parent">
parent: <xsl:value-of select="util:Lo calName(.)"/>
child: <xsl:value-of select="util:Lo calName(child)"/>
grandchild: <xsl:value-of select="util:Lo calName(child/grandchild)"/>
</xsl:template>
</xsl:stylesheet>

When applied to your XML it outputs:

parent: parent
child: child
grandchild: grandchild

--
Oleg Tkachenko [XML MVP]
http://blog.tkachenko.com