I am trying to work out a regular expression which will validate a
password box.
The following rules apply
Must be 8 characters
Must have at least one digit (0-9) and at least one character (a-z or
A-Z)
No special characters allowed except for full stop.
I am struggling to get to grips with regular expressions. Can anyone
help me with this please.
Thanks in anticipation
Ros Lee
14  3382 
Maybe we need to && the conditional statements with three regex patterns:
r1 = [a-zA-Z0-9]{8}
r2 = [a-zA-Z]{1,7}
r3 = [0-9]{1,7}
or just use r2 "anded" to r3 with a string length of 8.
Eg.:
option 1: (I like this one better. It has a more definitive and tighter
constraint on the string pattern compared to opt2)
if ((Regex.IsMatch (sPassword, r1)) &&
(Regex.IsMatch( sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)))
option 2:
if ((Regex.IsMatch (sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)) &&
(sPassword.Leng th == 8)) http://www.regular-expressions.info/ has a good tutorial on regex.
Try it see if either works and good luck,
/Js.
"Roz Lee" <ro**@panztel.c om> wrote in message
news:b7******** *************** *@posting.googl e.com... I am trying to work out a regular expression which will validate a
password box.
The following rules apply
Must be 8 characters
Must have at least one digit (0-9) and at least one character (a-z or
A-Z)
No special characters allowed except for full stop.
I am struggling to get to grips with regular expressions. Can anyone
help me with this please.
Thanks in anticipation
Ros Lee
Maybe we need to && the conditional statements with three regex patterns:
r1 = [a-zA-Z0-9]{8}
r2 = [a-zA-Z]{1,7}
r3 = [0-9]{1,7}
or just use r2 "anded" to r3 with a string length of 8.
Eg.:
option 1: (I like this one better. It has a more definitive and tighter
constraint on the string pattern compared to opt2)
if ((Regex.IsMatch (sPassword, r1)) &&
(Regex.IsMatch( sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)))
option 2:
if ((Regex.IsMatch (sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)) &&
(sPassword.Leng th == 8)) http://www.regular-expressions.info/ has a good tutorial on regex.
Try it see if either works and good luck,
/Js.
"Roz Lee" <ro**@panztel.c om> wrote in message
news:b7******** *************** *@posting.googl e.com... I am trying to work out a regular expression which will validate a
password box.
The following rules apply
Must be 8 characters
Must have at least one digit (0-9) and at least one character (a-z or
A-Z)
No special characters allowed except for full stop.
I am struggling to get to grips with regular expressions. Can anyone
help me with this please.
Thanks in anticipation
Ros Lee
Just out of curiousity - why use regular expressions? Your problem is
just a few lines of non-regular expression code - why not just code
it the boring old way?
Just out of curiousity - why use regular expressions? Your problem is
just a few lines of non-regular expression code - why not just code
it the boring old way?
Hi Jimi, Just out of curiousity - why use regular expressions? Your problem is
just a few lines of non-regular expression code - why not just code
it the boring old way?
I am almost writting that forever however in this case, I think it will
needs more lines.
What did you think of?
Cor
Hi Jimi, Just out of curiousity - why use regular expressions? Your problem is
just a few lines of non-regular expression code - why not just code
it the boring old way?
I am almost writting that forever however in this case, I think it will
needs more lines.
What did you think of?
Cor
I think you can use a positive lookahead to put the "and" into the regex:
"^(?=.*\d)( ?=.*[a-zA-Z])(?:.{8,})$"
I tested it only on a few cases, but it seems to work.
(I assume for password verification efficiency isn't that important)
Niki
"John Smith" <.@.> wrote in news:De******** *********@twist er.socal.rr.com ... Maybe we need to && the conditional statements with three regex patterns:
r1 = [a-zA-Z0-9]{8}
r2 = [a-zA-Z]{1,7}
r3 = [0-9]{1,7}
or just use r2 "anded" to r3 with a string length of 8.
Eg.:
option 1: (I like this one better. It has a more definitive and tighter
constraint on the string pattern compared to opt2)
if ((Regex.IsMatch (sPassword, r1)) &&
(Regex.IsMatch( sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)))
option 2:
if ((Regex.IsMatch (sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)) &&
(sPassword.Leng th == 8))
http://www.regular-expressions.info/ has a good tutorial on regex.
Try it see if either works and good luck,
/Js.
"Roz Lee" <ro**@panztel.c om> wrote in message
news:b7******** *************** *@posting.googl e.com... I am trying to work out a regular expression which will validate a
password box.
The following rules apply
Must be 8 characters
Must have at least one digit (0-9) and at least one character (a-z or
A-Z)
No special characters allowed except for full stop.
I am struggling to get to grips with regular expressions. Can anyone
help me with this please.
Thanks in anticipation
Ros Lee
I think you can use a positive lookahead to put the "and" into the regex:
"^(?=.*\d)( ?=.*[a-zA-Z])(?:.{8,})$"
I tested it only on a few cases, but it seems to work.
(I assume for password verification efficiency isn't that important)
Niki
"John Smith" <.@.> wrote in news:De******** *********@twist er.socal.rr.com ... Maybe we need to && the conditional statements with three regex patterns:
r1 = [a-zA-Z0-9]{8}
r2 = [a-zA-Z]{1,7}
r3 = [0-9]{1,7}
or just use r2 "anded" to r3 with a string length of 8.
Eg.:
option 1: (I like this one better. It has a more definitive and tighter
constraint on the string pattern compared to opt2)
if ((Regex.IsMatch (sPassword, r1)) &&
(Regex.IsMatch( sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)))
option 2:
if ((Regex.IsMatch (sPassword, r2)) &&
(Regex.IsMatch( sPassword, r3)) &&
(sPassword.Leng th == 8))
http://www.regular-expressions.info/ has a good tutorial on regex.
Try it see if either works and good luck,
/Js.
"Roz Lee" <ro**@panztel.c om> wrote in message
news:b7******** *************** *@posting.googl e.com... I am trying to work out a regular expression which will validate a
password box.
The following rules apply
Must be 8 characters
Must have at least one digit (0-9) and at least one character (a-z or
A-Z)
No special characters allowed except for full stop.
I am struggling to get to grips with regular expressions. Can anyone
help me with this please.
Thanks in anticipation
Ros Lee
> Cor Ligthertwrote:
I am almost writting that forever however in this case, I think it
will needs more lines. What did you think of? Cor
Suppose the regular expression approach takes 4 lines and 1 hour. My
approach to this trivial problem takes 12 lines and 5 minutes. This
is an easy business decision - there is no need to minimize the
number of lines of code if the tradeoff is this drastic.
I can see using regular expressions for complex problems, but it's
massive overkill for small problems. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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