mysql_num_rows( ): supplied argument is not a valid MySQL result resource

[macdalor]

Hi! I'm completely new to all dev and trying to put a website together using MySQLI and PHP; was running fine until I try to gather the DB content with the following script:

<?
$username="xxxxxx";
$password="xxxxxx";
$database="maxalien_davidloran";
 
mysql_connect(localhost,$username,$password);
@mysql_select_db($database) or die( "Unable to select database");
$query="SELECT * FROM contacts";
 
$result=mysql_query($query);
 
$num=mysql_num_rows($result);
 
 
mysql_close();
 
echo "<b><center>Database Output</center></b><br><br>";
 
$i=0;
while ($i < $num) {
 
$username=mysql_result($result,$i,"username");
$password=mysql_result($result,$i,"password");
$email=mysql_result($result,$i,"email");
 
echo "<b>$first $last</b><br>Phone: $phone<br>Mobile: $mobile<br>Fax: $fax<br>E-mail: $email<br>Web: $web<br><hr><br>";
 
$i++;
}
 
?>
 

getting the following error mesg when running it:

Warning: mysql_num_rows( ): supplied argument is not a valid MySQL result resource in /home/maxalien/public_html/davidloran/test/userCake/dbresult.php on line 12
Database Output

Let me know if you need more info and thx for your help

[macdalor]

is anyone able to help please?

[code green]

Something is failing here

mysql_connect(localhost,$username,$password); 
@mysql_select_db($database) or die( "Unable to select database"); 
$query="SELECT * FROM contacts"; 
 
$result=mysql_query($query); 
 
$num=mysql_num_rows($result); 
 

You can help yourself by removing the error supression '@' and
testing the returns using if() and mysql_error().

Also, further down you are closing the database connection then continuing to use it