Hi,
I have wrote two queries, one to find the average for one date, and the second query to find the average for another date. And I stored the results of the query to a local string object. Is there anyway to compare the two averages by getting the difference between the two. example query -
-
String myQuery = "" +
-
"select name, age, date, avg(count) from product where date=interval -7 Day + '2001-08-13' " +
-
" group by name ";
-
Let's say that I get another query for the next 7 days, how do I compare the two averages from the two queries?
Note: Using Mysql 5.0, and JDBC app to connect to DB, table, etc (works fine)
just need help with the query in my program
Thanks,
5 2360
Why not just compare the values that you have stored in those local string "objects" that you saved them to?
Thanks for the quick response, but how do I accomplish that? Can you provide a code snippet, or refer me to an article?
You convert a string to a number using Integer.parseIn t. You then compare the integers using the normal comparison operators.
Thanks, I was able to make the conversion from string to int. But my next question is how do I write the sql query to query the database to return the results using the new averages in which I converted to integers?
//newdailyCount is a string like "1.2222"
//firstAverage is an int - firstAverage=Integer.parseInt(newdailyCount);
Here is the query I tried to return the results after I get the avg of the previous seven days, and the next seven days, then I want to subtract the avgs of the two. But the query doesn't work. - # String myQuery = "" +
-
# "select name, age, date, avg(count) from product where newdailyCount=(firstAverage -10) " +
-
# " group by name ";
Thanks,
Can someone provide a code snippet or suggestions for the query above?
thanks,
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