Hi All,
I've defined a table (m) with an double field (bedrag) in it and when
I execute the next statement:
INSERT INTO m (bedrag) VALUES('-7000,00');
the value get stored correctly.
I've written a PHP-script which does the following:
$SQL="INSERT INTO m (getal) VALUES('$bedrag ')";
$res=mysql_quer y($SQL);
echo "SQL = ".$SQL."<br >";
When I look at the display from the echo statement it looks like:
SQL = INSERT INTO m (getal) VALUES('-7.000,00')
So that looks OK. But when I do a SELECT * FROM m; in MySQL the stored
value is -7,00 instead of -7000,00. I've defined the bedrag field as
DOUBLE(10,2) so that should not be a problem.
I'm using PHP 4.3.2 and MySQL 4.0.20a.
Can anyone tell me what I'm doing wrong here?
Richard. 2 4932
"Richard van Denzel" wrote: Hi All,
I’ve defined a table (m) with an double field (bedrag) in it and when I execute the next statement:
INSERT INTO m (bedrag) VALUES(’-7000,00’);
the value get stored correctly.
I’ve written a PHP-script which does the following:
$SQL="INSERT INTO m (getal) VALUES(’$bedrag ’)"; $res=mysql_quer y($SQL); echo "SQL = ".$SQL."<br >";
When I look at the display from the echo statement it looks like:
SQL = INSERT INTO m (getal) VALUES(’-7.000,00’)
So that looks OK. But when I do a SELECT * FROM m; in MySQL the
stored value is -7,00 instead of -7000,00. I’ve defined the bedrag field as DOUBLE(10,2) so that should not be a problem. I’m using PHP 4.3.2 and MySQL 4.0.20a.
Can anyone tell me what I’m doing wrong here?
Richard.
What’s "," in 7.000,00. Can you try removing the "," and see
what happens?
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Richard van Denzel wrote: I've defined a table (m) with an double field (bedrag) in it and when I execute the next statement:
INSERT INTO m (bedrag) VALUES('-7000,00');
As far as I can tell from the documentation, MySQL does not support the
German-style numeric format. You must use "." as the decimal point, and
no thousands separator is supported.
Perhaps one could write a UDF to parse strings in the German numeric
format, and convert them to decimal values before inserting them.
I don't know how to do this, but I imagine it would be possible.
Regards,
Bill K. This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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Hi All,
I've defined a table (m) with an double field (bedrag) in it and when
I execute the next statement:
INSERT INTO m (bedrag) VALUES('-7000,00');
the value get stored correctly.
I've written a PHP-script which does the following:
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