Shell Script awk problem , please advice

[DannyMc]

Hi, i am currently writing a script to delete the directory named with number.

Example:
in /usr/
i have
/usr/101
/usr/102 ...... /usr/200

This is the command i type and it works, i got the directory listed where the number is <150

ls -l /usr/ | grep ^d | awk '{ if ( $9 < 150) print $9 }'

So i applied it to the script, and it is not working especially at awk if else comparison, screen printed ALL number (101 -200). I am suspecting the error is in awk command there. Please help.

#!/bin/bash -xv
COPYKEEP="10"
LATEST="200"
KEEPFROM=`expr $LATEST - $COPYKEEP`
 
if [ $KEEPFROM -gt 0 ]
then
 
# Find which to delete.
ls -l /usr/ | grep ^d |  awk '{ if ( $9 < $KEEPFROM ) print $9 }'
fi

[ashitpro]

#!/bin/bash -xv
COPYKEEP="10"
LATEST="200"
KEEPFROM=`expr $LATEST - $COPYKEEP`
echo $KEEPFROM
if [ $KEEPFROM -gt 0 ]
then
# Find which to delete.
ls -l /usr/ | grep ^d |  awk -v p=$KEEPFROM '{ if ( $9 < p ) print $9 }'
fi
 

check the above script...
you can not use shell variables in awk directly..
it needs to be assigned to awk variable and then use it...
in Example we'r assigning it to 'p'

[DannyMc]

It works!!

Thank you so much!

[DannyMc]

Hi again,

i have tried to delete the file in awk using method found via google.

ls -l /usr1/ | grep ^d | grep -v current | awk -v p=103 '{ if ( $9 < p ) system("rm -rf " "\""$9"\"") }'

This is working , however when i apply this to the script

echo " ls -l /usr1/ | grep ^d | grep -v current | awk -v p=103 '{ if ( $9 < p ) system("rm -rf " "\""$9"\"") }' "
 

The quoting is very confusing, can anyone help?

[ashitpro]

Hi again,

i have tried to delete the file in awk using method found via google.

ls -l /usr1/ | grep ^d | grep -v current | awk -v p=103 '{ if ( $9 < p ) system("rm -rf " "\""$9"\"") }'

This is working , however when i apply this to the script

echo " ls -l /usr1/ | grep ^d | grep -v current | awk -v p=103 '{ if ( $9 < p ) system("rm -rf " "\""$9"\"") }' "
 

The quoting is very confusing, can anyone help?

I didn't need any complex quoting...
Next statement worked for me in shell script as well as on command line...

ls -l /usr/ | grep ^d | grep -v current | awk -v p=103 '{ if ( $9 < p ) system("rm -rf /usr/" $9) }'

[DannyMc]

Again, Thank you. It works :)

[ghostdog74]

there's actually another less cumbersome way to do it.

rm -rf /usr/[0-1][0-9][0-9]
rm -rf /usr/200