Hi All,
I have defined a function
function fct(arr) { ... }
When I call this function, I prefer to write
fct(Array(item1 , item2));
But if I write
fct(new Array(item1, item2));
The code above works as well. But Will it cause any memory leaks?
--
best regards
Xu, Qian (stanleyxu) 2 1743
On Mar 15, 8:55 am, "Xu, Qian" <no_re...@micro soft.comwrote:
Hi All,
I have defined a function
function fct(arr) { ... }
When I call this function, I prefer to write
fct(Array(item1 , item2));
But if I write
fct(new Array(item1, item2));
The code above works as well. But Will it cause any memory leaks?
--------------
<URL: http://www.ecma-international.o rg/publications/standards/Ecma-262.htm>
15.4.1 The Array Constructor Called as a Function
When Array is called as a function rather than as a constructor, it
creates and initialises a new Array
object. Thus the function call Array(...) is equivalent to the object
creation expression
new Array(...) with the same arguments.
--------------
Of course, you need to test the implementations to see if they
conform. I would guess "new Array()" is safer than "Array()".
The advantage of "new Array()" looks the same as your own JavaScript
constructors "new MyConstructor() "
Peter
On Mar 16, 1:55*am, "Xu, Qian" <no_re...@micro soft.comwrote:
Hi All,
I have defined a function
* *function fct(arr) { ... }
When I call this function, I prefer to write
* *fct(Array(item 1, item2));
But if I write
* *fct(new Array(item1, item2));
The code above works as well.
Further to what Peter wrote, you could also use an array literal:
fct([item1, item2]);
--
Rob This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics |
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