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Help me understand this JSON eval problem please

Why is this:

eval('[{\"active":"tru e"}]')

is OK, but

eval('{"active" :"true"}') tells me I'm missing ";" ?

Then why is it that if I put parentheses around the second statement:

eval('({"active ":"true"})' )

Then it's OK again?

Thanks in advance!
Ray

Jul 31 '06 #1
3 3635
ra********@yaho o.com wrote:
Why is this:

eval('[{\"active":"tru e"}]')

is OK, but

eval('{"active" :"true"}') tells me I'm missing ";" ?

Then why is it that if I put parentheses around the second statement:

eval('({"active ":"true"})' )

Then it's OK again?

Thanks in advance!
Ray

Because:

[{"active":"true "}]

is a valid expression, but

{"active":"true "}

is a syntax error at the colon.

The first one defines an array containing an object, in the second one
the '{' is starting a block, not defining an object.

See the Ecmascript language specification, section 12.4 Expression
statement:
Note that an ExpressionState ment cannot start with an opening curly
brace because that might make it ambiguous with a Block. Also, an
ExpressionState ment cannot start with the function keyword because
that might make it ambiguous with a FunctionDeclara tion.
Jul 31 '06 #2
ra********@yaho o.com wrote:
Why is this:

eval('[{\"active":"tru e"}]')

is OK, but

eval('{"active" :"true"}') tells me I'm missing ";" ?

Then why is it that if I put parentheses around the second statement:

eval('({"active ":"true"})' )

Then it's OK again?
A javascript Expression Statement may not commence with an opening
brace, so that it cannot be ambiguous along side Block Statements. The
- eval - function is supposed to execute a string as if it satisfied
the production rules for a Program, and Programs are made up of
statements, so - eval - must see the first opening brace and starting a
Block statement, and then the absence of a semicolon before the colon
is a syntax error. With the parentheses the opening brace is becomes
part of a parenthesised Expression and so must be interpreted as the
start of an object literal, and the parenthesised Expression becomes an
Expression Statement (as no other production can put an opening
parenthesis at the start of a Statement).

Richard.

Jul 31 '06 #3
Ray
Thanks Duncan, Richard, for the explanations!

Cheers,
Ray

ra********@yaho o.com wrote:
Why is this:

eval('[{\"active":"tru e"}]')

is OK, but

eval('{"active" :"true"}') tells me I'm missing ";" ?

Then why is it that if I put parentheses around the second statement:

eval('({"active ":"true"})' )

Then it's OK again?

Thanks in advance!
Ray
Jul 31 '06 #4

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