How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.39999999999 998 instead of 191.40.
<html>
<head>
<title>floats.h tm</title>
</head>
<body>
<script type="text/javascript">
var a = [46.57,45.00,45. 00,54.83];
var t = 0.00;
for (var i=0; i<a.length; i++) {
alert(t + "\n" + a[i])
t += a[i];
}
alert(t + " = 191.40 ?")
</script>
</body>
</html>
Thanks in advance.
P.S. This FAQ doesn't help: http://jibbering.com/faq/#FAQ4
4.7 Why does 5 * 1.015 != 5.075 or 0.05+0.01 != 0.06? 8  2315 
McKirahan wrote: How do I add floating point numbers accurately?
Using '+'.
A simpler demonstration of your problem:
alert(136.57+54 .83);
shows 191.39999999999 998
P.S. This FAQ doesn't help:
http://jibbering.com/faq/#FAQ4
4.7 Why does 5 * 1.015 != 5.075 or 0.05+0.01 != 0.06?
It should help. It says:
Javascript numbers are represented in binary as IEEE-754 Doubles, with
a resolution of 53 bits, giving an accuracy of 15-16 decimal digits;
integers up to about 9e15 are precise, but few decimal fractions are.
in this case 136.57 is stored internally as 136.56999999999 999,
54.83 is stored internally as 54.829999999999 998.
Adding these together and reducing the result to the appropriate precision
gives the answer displayed above.
If you want to display a friendlier value as the result, change your final
alert to:
alert(t.toFixed (2) + " = 191.40 ?");
"McKirahan" <Ne**@McKirahan .com> wrote: How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.3999999999 9998 instead of 191.40.
That's the way it is. Not all decimal fractions can be represented
exactly as binary fractions, which is how floating point numbers are
stored. Floating point numbers are necessarily somewhat imprecise. In
this case the imprecision is on the order of 10**-12, which is
extremely tiny.
--
Tim Slattery Sl********@bls. gov
McKirahan wrote: How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.39999999999 998 instead of 191.40.
Some variation of the following:
/Math.round(Math .pow(10,x)*(46. 57+45.00+45.00+ 54.83))/Math.pow(10,x);/
Where x equals number of digits required to the right of the decimal point.
Mick
If performance is not an issue you could write some arbitrary precision
mathematics.
I.e. you store a number as an array of digits, and perform long
division, long addition etc.
McKirahan said the following on 10/5/2005 7:44 AM: How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.39999999999 998 instead of 191.40.
You convert them to whole numbers, do your math, and then use string
manipulation to put the decimal back where you want it along with
leading and/or trailing zeroes.
P.S. This FAQ doesn't help:
http://jibbering.com/faq/#FAQ4
4.7 Why does 5 * 1.015 != 5.075 or 0.05+0.01 != 0.06?
4.7 along with 4.6 do answer your question, they just aren't very well
worded and/or explained enough to make sense to anybody that doesn't
understand it to start with.
--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq & newsgroup weekly
McKirahan <Ne**@McKirahan .com> wrote in message news:GM******** ************@co mcast.com... How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.39999999999 998 instead of 191.40.
If you happen to be handling money, it's preferable to avoid floating point calculations by working in pennies, then
formatting the result.
var pennies=12305
var dollars=Math.fl oor( pennies / 100 ), cents = pennies % 100;
result = dollars + '.' + ((cents < 10) ? ('0' + cents) : cents);
--
S.C.
Tim Slattery wrote: McKirahan wrote:How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.399999999 99998 instead of 191.40.
That's the way it is. Not all decimal fractions can be
represented exactly as binary fractions, which is how
floating point numbers are stored. Floating point numbers
are necessarily somewhat imprecise. In this case the
imprecision is on the order of 10**-12, which is extremely
tiny.
And it isn't a characteristic restricted to binary representations of
numbers. How precise is the decimal fraction representation of 1/3? And
would it be reasonable to complain that 3.33 + 3.33 + 3.33 did not
result in 1?
Richard.
Richard Cornford said the following on 10/5/2005 7:29 PM: Tim Slattery wrote:
McKirahan wrote:
How do I add floating point numbers accurately?
The following adds the 4 numbers
46.57, 45.00, 45.00, and 54.83 to give
191.39999999 999998 instead of 191.40.
That's the way it is. Not all decimal fractions can be
represented exactly as binary fractions, which is how
floating point numbers are stored. Floating point numbers
are necessarily somewhat imprecise. In this case the
imprecision is on the order of 10**-12, which is extremely
tiny.
And it isn't a characteristic restricted to binary representations of
numbers. How precise is the decimal fraction representation of 1/3? And
would it be reasonable to complain that 3.33 + 3.33 + 3.33 did not
result in 1?
Umm, yes it would since it should either result in 9.99 or 10, not 1 :)
--
Randy
comp.lang.javas cript FAQ - http://jibbering.com/faq & newsgroup weekly This thread has been closed and replies have been disabled. Please start a new discussion. Similar topics | |
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