I have a string with 10 charaters 123456789A.
I only want the first 6 charaters followed by the last two...getting
rid of the 7th and 8th charaters.
If I use document.forms[0].MyTextBox.valu e =
TheString.subst ring([0-5])...I get the first 6 charaters.
([0-5],8,9) does not work nor does ([0-5],[8-9]) and I get just as bad
results with (0,1,2,3,4,5,8, 9)
how do I get a string with the 7th and 8th charaters missing?
3  1374 
On 1 Sep 2004 08:49:48 -0700, Abby Lee <ab*******@hotm ail.com> wrote: I have a string with 10 charaters 123456789A.
I only want the first 6 charaters followed by the last two... getting
rid of the 7th and 8th charaters.
If I use document.forms[0].MyTextBox.valu e =
TheString.subst ring([0-5])...I get the first 6 charaters.
([0-5],8,9) does not work nor does ([0-5],[8-9]) and I get just as bad
results with (0,1,2,3,4,5,8, 9)
I'm not quite sure what your expectations are, but the substring method
only takes two arguments: the zero-based index of the starting character,
and the index of a second character. The returned string doesn't include
the character specified by the second index.
how do I get a string with the 7th and 8th charaters missing?
To do what you want, you'll need to call the method twice:
str.substring(0 , 6) + str.substring(8 )
Mike
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Michael Winter
Replace ".invalid" with ".uk" to reply by e-mail.
Abby Lee wrote: I have a string with 10 charaters 123456789A.
I only want the first 6 charaters followed by the last two...getting
rid of the 7th and 8th charaters.
If I use document.forms[0].MyTextBox.valu e =
TheString.subst ring([0-5])...I get the first 6 charaters.
([0-5],8,9) does not work nor does ([0-5],[8-9]) and I get just as bad
results with (0,1,2,3,4,5,8, 9)
how do I get a string with the 7th and 8th charaters missing?
theString="1234 56789A"
alert(theString .substring(0,6) +theString.subs tring(8))
Mick
JRS: In article <80************ **************@ posting.google. com>,
dated Wed, 1 Sep 2004 08:49:48, seen in news:comp.lang. javascript, Abby
Lee <ab*******@hotm ail.com> posted : I have a string with 10 charaters 123456789A.
I only want the first 6 charaters followed by the last two...getting
rid of the 7th and 8th charaters.
If I use document.forms[0].MyTextBox.valu e =
TheString.subs tring([0-5])...I get the first 6 charaters.
([0-5],8,9) does not work nor does ([0-5],[8-9]) and I get just as bad
results with (0,1,2,3,4,5,8, 9)
how do I get a string with the 7th and 8th charaters missing?
Str1 = "123456789A "
Str2 = Str1.replace(/^(......)../, "$1") // 1234569A
or Str2 = Str1.replace(/^(.{6}).{2}/, "$1") // 1234569A
Method is best suited to fixed patterns, but can be adapted for variable
numbers.
--
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