[HTML]id=request.getParameter("txtId");
51: pwd=request.getParameter("txtPwd");
52: rslogin=getAllData("select * from login where username='"+id+"' and password='"+pwd+"'");
53: while(rslogin.next())
54: {
55: flag=1;
56: session.setAttribute("UserId",id); [/HTML]
The above given is my coding.In my login table i have username and password.
But when iam excecuing the application with Tomcat following error is occuring.
org.apache.jasper.JasperException: An exception occurred processing JSP page /myLogTest.jsp at line 53
Stacktrace:
org.apache.jasper.servlet.JspServletWrapper.handle JspException(JspServletWrapper.java:515)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:426)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet .java:803)
root cause
java.lang.NullPointerException
org.apache.jsp.myLogTest_jsp._jspService(myLogTest _jsp.java:170)
org.apache.jasper.runtime.HttpJspBase.service(Http JspBase.java:70)
javax.servlet.http.HttpServlet.service(HttpServlet .java:803)
org.apache.jasper.servlet.JspServletWrapper.servic e(JspServletWrapper.java:384)
org.apache.jasper.servlet.JspServlet.serviceJspFil e(JspServlet.java:320)
org.apache.jasper.servlet.JspServlet.service(JspSe rvlet.java:266)
javax.servlet.http.HttpServlet.service(HttpServlet .java:803)
What i can Do ? Pleas Help me ...... :)