socket error when reading ip address from console

[diegoblin]

hello, i have this issue.Every time i use sockets if i use a "String" as a parameter the connection resets. but if i put the ip address like this "127.0.0.1" it okay.

and i got this message if i use a string i read from the console

Exception in thread "main" java.net.Socket Exception: Connection r
at java.net.Socket InputStream.rea d(Unknown Source)
at sun.nio.cs.Stre amDecoder.readB ytes(Unknown Source)
at sun.nio.cs.Stre amDecoder.implR ead(Unknown Source)
at sun.nio.cs.Stre amDecoder.read( Unknown Source)
at java.io.InputSt reamReader.read (Unknown Source)
at java.io.Buffere dReader.fill(Un known Source)
at java.io.Buffere dReader.readLin e(Unknown Source)
at java.io.Buffere dReader.readLin e(Unknown Source)
at ServidorProyect o.mensajero(Ser vidorProyecto.j ava:141)
at Menu.selecciona Opcion(Proyecto .java:85)
at Menu.mostrarMen u(Proyecto.java :56)
at Proyecto.main(P royecto.java:20 2)

 
ClienteProyecto(String dirIP)throws IOException
    {
 
 
            InetAddObj = InetAddress.getByName(dirIP);// error
            InetAddObj = InetAddress.getByName("127.0.0.1");// correct uh?
 
            System.out.println("Conectando a : " + InetAddObj);
 
            ServidorProyecto SPObj = new ServidorProyecto();
 
            SocketObj = new Socket(InetAddObj, SPObj.devuelvePuerto());
 
 
 
    }
 
 
 

[JosAH]

Print out your String parameter dirIP and check what's wrong with it.

kind regards,

Jos

[diegoblin]

I already did it, for example if i type 127.0.0.1 and print that String it says 127.0.0.1, also i checked the string length with dirIp.length() and it's correct!

[JosAH]

@diegoblin
Can you show us the code that produced that String IP address? There must be something wrong in there (maybe a trailing \n character).

kind regards,

Jos

[diegoblin]

I'm using this class to read from console

class LeeConsola
{
 
    String devuelveCadena () throws IOException
    {
        BufferedReader BRobj = new BufferedReader(new InputStreamReader(System.in));
 
        char caracterEntrada;
        String cadena = "";
 
 
        do
        {
            caracterEntrada = (char)  BRobj.read();
            cadena = cadena + caracterEntrada;
        } while (caracterEntrada != '\r');
 
        return cadena;
    }
 
 
 
}
 

and the code where i send the String parameter is this

 
LeeConsola leeObj = new LeeConsola();
                String cadenaIp = "";
                System.out.println("Dame la direccion ip");
                cadenaIp = leeObj.devuelveCadena();
 
                ClienteProyecto CPObj = new ClienteProyecto(cadenaIp.substring(0,cadenaIp.length() - 1));// to get rid of /r
 

[JosAH]

@diegoblin
Suppose you type abc<enter>, the cadena String ends up with four characters: a, b, c and \r. You should not store the trailing \r character. btw. the BufferedReader class has a readLine() method that takes care of all the details.

kind regards,

Jos

[r035198x]

Also, these days people seem to prefer the Scanner or Console classes for getting input from the console