Printing numbers along the side of a program

[JavaStudent07]

File file=new File("H:/Numbers.java");
String Text="";
int intNumber=1;
BufferedReader lineIn=new BufferedReader(new FileReader(file));
 
try
{
Text=lineIn.readLine();
}
 
catch(FileNotFoundException e)
{
System.out.println("The file you entered was not found.");
System.exit(0);
}
 
try
{
Text=lineIn.readLine();
}
 
catch(IOException b)
{
System.out.println("ERROR! Please try again.");
}
 
while(linetext!=null)
{
System.out.print(intNumber+" "+Text);
intNumber=(intNumber+1);
System.out.print("\n");
 
try
{
Text=lineIn.readLine();
}
 
catch(IOException d)
{
System.out.println("ERROR! please try again.");
}
}
}

[JavaStudent07]

^^^^^^look up for code^^^^^^^^^^^
if anyone knows a more efficient way of printing numbers along the side of a program, please let me know
(for a print out the teacher is looking for;
1 public class main Blah
2 etc.

[JavaStudent07]

this is not high priority, if you dont feel like helping dont bother because it works, i'm just looking for a more efficient method that i can do quick in case i need to use this program in the future

[horace1]

this is not high priority, if you dont feel like helping dont bother because it works, i'm just looking for a more efficient method that i can do quick in case i need to use this program in the future

you could simplify the code a bit, e.g.

  try
    {
    File file=new File("Numbers.java");
    BufferedReader lineIn=new BufferedReader(new FileReader(file));
    int intNumber=1;
    String linetext;
    while((linetext=lineIn.readLine())!=null)
       System.out.println((intNumber++)+" "+linetext);
    }
  catch(FileNotFoundException e)
   {
    System.out.println("The file you entered was not found.");
    System.exit(0);
   }
 catch(IOException d)
  {
   System.out.println("ERROR! please try again.");
  }
}
 

[JavaStudent07]

SWEET :) thats all i needed, helped A LOT :) Eupert and Roper give two thumbs up!