Accessing a method inside of an object that is stored in a vector...

[da Vinci]

I have been trying to post to .help all day but nothing is going
through. Will try it here and hope it does....

I am trying to access a getData() method that simply returns a stored
integer value from an object that is stored in a vector. I have tried
to do this but cannot get the notation correct. I tried google groups
and the only thing I got from there was to pull the object from the
vector into a temperary object. That didnt work.

So, here is the code I have so far of making the temp object and
making sure it is actually pulling one out. I still connot figure out
how to access the getData() method.

Any hints are appreciated.

import java.util.Vecto r;

public class StackUser
{

public static void main(String argv[])
{

Vector vector = new Vector();

for (int i = 0; i < 100; i++)
vector.add(i, new StackNode());

System.out.prin tln(vector.get( 0));

Object tobj = vector.get(0);

System.out.prin tln(tobj);
}
}

public class StackNode
{

private int value = 0;
public StackNode()
{
value = (int)(Math.rand om());
}

public int getData()
{
return value;
}

}

[Raymond DeCampo]

da Vinci wrote:

I have been trying to post to .help all day but nothing is going
through. Will try it here and hope it does....

I am trying to access a getData() method that simply returns a stored
integer value from an object that is stored in a vector. I have tried
to do this but cannot get the notation correct. I tried google groups
and the only thing I got from there was to pull the object from the
vector into a temperary object. That didnt work.

So, here is the code I have so far of making the temp object and
making sure it is actually pulling one out. I still connot figure out
how to access the getData() method.

After getting the object from the Vector, you must cast it to the proper
type. Look up the cast syntax in your reference material.

If you use the so-called "generics" in Java 1.5, the cast is unnecessary.

HTH,
Ray

--
XML is the programmer's duct tape.